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Klio2033 [76]
3 years ago
10

What is the median of this set of measurements? 10cm, 15cm, 15cm, 18cm, 20cm.

Mathematics
2 answers:
Alinara [238K]3 years ago
4 0

Answer:

15 cm

Step-by-step explanation:

Median means middle number

10,15,15,18,20

Marina86 [1]3 years ago
3 0

Answer:

15 cm

Step-by-step explanation:

The median is the number in the middle of a data set.

First, arrange the data from least to greatest.

10 cm, 15 cm, 15 cm, 18 cm, 20 cm

Now, take one number off each end of the data set until the middle number is reached.

10 cm, 15 cm, 15 cm, 18 cm, 20 cm

15 cm, 15 cm, 18 cm

15 cm

Therefore the median of the set of measurements is 15 cm.

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Refer to the Exhibit Student Grades. The professor has informed the class that 7.93 percent of her students received grades of A
Marta_Voda [28]

This question is incomplete, the complete question is;

Refer to the Exhibit Student Grades. A professor at a local university noted that the grades of her students were normally distributed with a mean of 73 and a standard deviation of 11.

The professor has informed the class that 7.93 percent of her students received grades of A. What is the minimum score needed to receive a grade of A

Answer:

the minimum score needed to receive a grade of A is 88.51

Step-by-step explanation:

Given the data in the question;

Let x represent the grades of the students that were normally distributed with mean μ = 73 and standard deviation σ = 11.

so, The professor has informed the class that 7.93 percent of her students received grades of A

the minimum score needed to receive a grade of A will be:

P( X > x ) = 7.93 %

P( X > x ) = 0.0793

1  - P( X ≤ x ) = 0.0793

- P( X ≤ x ) = 0.0793 - 1

- P( X ≤ x ) = - 0.9207

P( X ≤ x ) = 0.9207

⇒ P( X-μ/σ ≤ x-μ/σ ) = 0.9207

so, x-μ/σ = InvNormal( 0.9207 )  

x-μ/σ = 1.41

(x - 73) / 11 = 1.41

(x - 73) = 1.41 × 11

(x - 73)  = 15.51

x = 15.51 + 73

x = 88.51

Therefore, the minimum score needed to receive a grade of A is 88.51

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