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2 years ago

11

How many titles 250mm square will be needed to cover s kitchen floor of length 3m and breath 2.5m . The answer should be in the

unit metre square

1 answer:

nordsb [41]2 years ago

6 0

Answer:

30,000 tiles

Step-by-step explanation:

Area of tile = 250mm^2 = 0.25m^2

Total area of kitchen = 3*2.5 = 7.5m^2

No of tiles = 7.5/0.25 = 30,000 tiles

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Simplify 14(1.2)^10?

noname [10]

1790988582563.6448is your answer. All you do is multiply 14 times 1.2, which equals 16.8. Then you do 16.8 times itself. 16.8 x 16.8 = 282.24. Then 282.24 times itself, and so on so forth.

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3 years ago

50 points find the area

mixer [17]

Answer:

B. 84 in²

Step-by-step explanation:

Split the area into two sections by extending 6 in segment.

We get a rectangle of 5 in x 10 in and a trapezoid.

<u>Rectangle:</u>

A = wl
A = 5*10 = 50 in²

<u>Trapezoid:</u>

A = 1/2(b₁ + b₂)h
A = 1/2((15 - 5) + 7)*(10 - 6) = 1/2*17*4 = 34 in²

<u>Total area:</u>

50 + 34 = 84 in²

4 0

2 years ago

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A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an

Nataly [62]

Answer:

The distance between the walls is 70 m.

Step-by-step explanation:

Given: A source of laser light is at point A on the ground between two parallel walls BE and CD . The walls are perpendicular to the ground that is

BE ⊥ ED and CD ⊥ ED

AB is a ray of light which strikes the wall on the left at point B which is 30 meters above the ground. that is BE = 30 m

AC is a ray of light which strikes the wall on the right at point C. The length of AC = 80 meters.

The ray AB makes an angle of 45 degrees with the ground that is m∠BAE = 45°

The ray AC makes an angle of 60 degrees with the ground that is m∠CAD = 60°

As shown is figure attached below.

WE have to find the distance between the walls that is Length of ED

Length of ED = EA + AD

Consider the Δ AEB,

Using trigonometric ratio,

$\tan\theta=\frac{perpendicular}{base}$

Here $\theta=45^{\circ}$ , perpendicular = 30 m and base we can find.

thus,

$\tan 45^{\circ}=\frac{30}{EA}$

We know $\tan 45^{\circ}=1$

thus, EA = 30 m

Consider the Δ AEB,

Using trigonometric ratio,

$\cos\theta=\frac{base}{hypotenuse}$

Here $\theta=60^{\circ}$ , hypotenuse = 80 m and base we can find.

thus, $\cos 60^{\circ}=\frac{base}{80}$

We know, $\cos 60^{\circ}=\frac{1}{2}$

thus, Base = 40 m

AD = 40 m

Thus, the distance between the walls that is the length of ED = 30 + 40 = 70 m

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3 years ago

A 25-foot tall flagpole casts a 42-foot shadow. What is the angle (to the neasrest tenth of degree) that the sun hits the flagpo

Maurinko [17]

Tan^-1 (tan x) = 42/25
x=tan^-1 42/25

x= 59.237 degrees.

8 0

3 years ago

An altitude of a right triangle to its hypotenuse divides this hypotenuse into two segments that measure 9cm, and 16cm. What are

ozzi

Answer:

Step-by-step explanation:

Let a be the length of the altitude, then from the given triangles, applying the basic proportionality theorem, we get

$\frac{BD}{AD}=\frac{DC}{BD}$

⇒ $(BD)^{2}=DC{\times}AD$

⇒ $(BD)^2=9{\times}16$

⇒ $BD=\sqrt{144}$

⇒ $BD=12 cm$

Thus, the length of altitude is: 12 cm.

Now, $\frac{AB}{AD}=\frac{AC}{AB}$

⇒ $(AB)^{2}=220$

⇒ $AB= 14.83 cm$

Also, $\frac{BC}{DC}\frac{AC}{BC}$

⇒ $(BC)^{2}=400$

⇒ $BC=20 cm$

Thus, the lengths of the legs of this triangle are 14.83 and 20 cm.

6 0

3 years ago

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