9. BX is a perpendicular bisector of AC. What is the

Simplify the expression:<br><br> 7(d - 1) + 2

Alinara [238K]

Answer: 7d-5

I hope it helps you!!!!!

3 0

2 years ago

Am i right brainliest going to first correct answer

Firdavs [7]

The solution to the inequality is -20.8 > p (imagine the symbol is the symbol for at least)

5 0

2 years ago

Read 2 more answers

Kirk went to a friend’s house after dinner. He left his house at 7:29pm and returned home at 8:05pm. How long was Kirk gone for?

liberstina [14]

Answer:

36 minutes

Step-by-step explanation:you look at it and solve it

3 0

3 years ago

Read 2 more answers

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below

mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

d) $MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

<u>e)</u> $s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0

2 years ago

Un joven retira el 25% de sus ahorros y gasta el 33.3% en adornos para su

ki77a [65]

Answer:

$3003.2

Step-by-step explanation:

Step 1

Paso 1

Averiguamos cuánto era el 25% de sus ahorros.

Se nos dice en la pregunta que gastó el 33.3% en decoraciones para su nueva casa y si los adornos cuestan $ 250.00.

Esto significa

33.3 % × x = 250

33.3 x/ 100 = 250

Cruz multiplicar

33.3x = 250 × 100

x = 25.000 / 33.3

x = 750.75075075

Por lo tanto, la cantidad o el costo de los adornos = 33.3% del 25% de sus ahorros = $ 750.8

Paso 2

De la pregunta:

Un joven retira el 25% de sus ahorros y

Por lo tanto:

Sea y = monto total de sus ahorros

25/100 × y = $ 750.8

25y = 100 × 750.8.

y = 100 × 750.8 / 25

y = $ 3003.2

Por lo tanto, tenía $ 3003.2 en su cuenta.

6 0

3 years ago