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2 years ago

Please help me for urgent

Mathematics

1 answer:

Keith_Richards [23]2 years ago

5 0

For question (ii) I'm not sure if the answer is correct or not because I don't understand the question asked ...

I hope I can help ....

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loris [4]

Answer:

31.41

Step-by-step explanation:

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6 0

3 years ago

Read 2 more answers

∠A and \angle B∠B are supplementary angles. If m\angle A=(x+6)^{\circ}∠A=(x+6) ∘ and m\angle B=(7x+30)^{\circ}∠B=(7x+30) ∘ , the

nikitadnepr [17]

Answer:

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Step-by-step explanation:

6 0

3 years ago

What number makes the equation true?

gtnhenbr [62]

Answer:

Step-by-step explanation:

the denominators are the same, so just add the two fractions on the right and subtract it from the answer on the left.

3500/7+210/7=3710/7

subtract 3710 from 3742

= 32

6 0

3 years ago

HELP PLS ASAP -5 = 5/12a pls evaluate

Setler79 [48]

Answer:

a = -12

Remember that when a variable is times with a number, you divide the number on both sides.

When a variable is divided by a number, you multiply the number on both sides.

Hope this helps you. Thank you !!

6 0

3 years ago

Erica plotted the three towns closest to her house on a graph with town AA at (9, 12), town BB at (9, 7) and town CC at (1, 1).

Sliva [168]

To compute the distance between the points, we can apply the distance formula as shown below.

$d = \sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2} }$

In which x₁ and x₂ are the x-coordinates and y₁ and y₂ are the y-coordinates of the two points. Thus, applying this with the segments AABB, AACC, and BBCC, we have

$\overline{AABB} = \sqrt{(9-9)^{2} + (12-7)^{2}} = 5$
$\overline{AACC} = \sqrt{(9-1)^{2} + (12-1)^{2}} = \sqrt{185}$
$\overline{BBCC} = \sqrt{(9-1)^{2} + (7-1)^{2}} = 10$

Now that we have the lengths of all the sides of ΔAABBCC, we can find the missing angles using the Law of Cosines.

Generally, we have

$c^{2} = a^{2} + b^{2} - 2abcosC$

or

$C = cos^{-1} (\frac{a^{2} + b^{2} - c^{2}}{2ab})$

Hence, we have

$\angle AA = cos^{-1} (\frac{(\sqrt{185})^{2} + 5^{2} - 10^{2}}{2(5)(\sqrt185)})$
$\angle BB= cos^{-1} (\frac{5^{2} + 10^{2} - (\sqrt{185})^{2}}{2(5)(10)})$
$\angle CC= cos^{-1} (\frac{10^{2} + (\sqrt{185})^{2} - 5^{2}}{2(5)(\sqrt{185})})$

Simplifying this, we have

$\angle AA = 36.03^{0}$
$\angle BB = 126.87^{0}$
$\angle CC = 17.10^{0}$

Thus, from this, we can arrange the angles from smallest to largest: ∠CC, ∠AA, and ∠BB.

Answer: ∠CC, ∠AA, and ∠BB

3 0

3 years ago

Please help me for urgent​

Please help me for urgent