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patriot [66]
3 years ago
15

Write the point slope form of an equation of the line through the points

Mathematics
2 answers:
denis23 [38]3 years ago
7 0

Answer:

the answer is D

how to try the values of the x and y

(x,y)

MA_775_DIABLO [31]3 years ago
4 0

Equation of a line:  y = mx + c,  where m is the slope and c is the y-intercept. To calculate the slope, we do so using the formula: m = \frac{y2 - y1}{x2 - x1}

Now plugging in our values, m = \frac{4 - (-3)}{-7 - (-2)}  = \frac{4 + 3}{-7 + 2} = \frac{7}{-5} = \frac{-7}{5}

So our slope m, is = -7/5

We can now input the value of the slope. But in this question, we cannot use the above equation of a line since we are asked to use a point-slope equation expression, so the equation is y - y1 = m(x - x1)

Now we plug in our values,

y - (-3) = \frac{-7}{5}(x -  (-2))\\y + 3 = \frac{-7}{5}(x + 2)

So the answer should be option D.

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Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

s=16.6 represent the sample deviation

\bar X=12.8 represent the sample mean

n =1003 is the sample size selected

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\alpha=1-0.99=0.01 represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

12.8 - 2.58 \frac{16.6}{\sqrt{1003}}=11.448

12.8 + 2.58 \frac{16.6}{\sqrt{1003}} =14.152

And the 99% confidence interval would be given (11.448;14.152).

We are confident that about 11 to 14 are the number of books that the people had read on the last year on average, at 1% of significance.

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Answer:

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Step-by-step explanation:

x represents “the number” so we would substitute this with a variable.

(I hope this helps! Have a great day AND STAN BTS)

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Answer:

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