4^-64^-24^3 algebra

Mathematics

1 answer:

Nana76 [90]2 years ago

7 0

$4^{-6} X 4^{-2} X 4^{3}$
$4^{-6-2+3}$
$4^{-5}$
$\frac{1}{1024}$ i.e. $9.76X10^{-4}$

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<h3>Answer: Choice A</h3>

Domain: x > 4
Range: y > 0

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Explanation:

We want to avoid having a negative number under the square root. Solving $x-4 \ge 0$ leads to $x \ge 4$

So it appears the domain could involve x = 4 itself; however, if we tried that x value, then we'd get a division by zero error.

So in reality, the domain is x > 4.

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The range of y = sqrt(x) is the set of positive real numbers. So y > 0 is the range for this equation. Shifting left and right does not affect the range, so the range of y = sqrt(x-4) is also y > 0.

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Therefore, the range of the given equation is y > 0

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The graph is shown below. We have a vertical asymptote at x = 4 and a horizontal asymptote at y = 0. The green curve is fenced in the upper right corner (northeast corner).