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soldi70 [24.7K]
2 years ago
11

A mosquito is walking at random on the nonnegative number line. She starts at $1$. When she is at $0$, she always takes a step $

1$ unit to the right, but, from any positive position on the line, she randomly moves left or right $1$ unit with equal probability. What is the expected number of times the mosquito will visit $0$ before the first time she visits $4$?
Mathematics
1 answer:
nikitadnepr [17]2 years ago
4 0

Answer:

The expected number of times is 4.

Step-by-step explanation:

Looking at the question, we see that this follows a geometric distribution because it is asking for the expected number of trials hat will bring about the FIRST SUCCESS. The probability of success is

\frac{1}{4}

Since it is a geometric distribution, we know that the expected value of a random variable X, E(X) that follows a geometric distribution is given as:

E(X) = 1/p where p is the probability of success.

Therefore, the expected number of times will be

E(X) = 1/(1/p) = 1/(1/4) = 4.

Hence, the expected number of times is 4.

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Matt and Tikka thought of the same number. Matt added 7 to that number and then doubled the result. He got 26. Tikka did the sam
Reptile [31]

Answer:

19

Step-by-step explanation:

Matt ended up with 26.

We reverse the steps he did to get the original number that both people thought of.

26 / 2 = 13

13 - 7 = 6

6 is the original number.

Tikka did the same operations but in the reverse order so...

6 X 2 = 12

12 + 7 = 19

3 0
3 years ago
What is the volume of the cuboid (the box) in this figure? (no need to enter the units)
poizon [28]

Answer:

220 cm

Step-by-step explanation:

Multiply length x width x height

22 x 5 x 2

110 x 2

220 cm

6 0
3 years ago
Marco is 8 years younger than his brother Paolo. If their product of their ages is 105, how old is Marco? plz help
Nina [5.8K]

Answer:

Marco's age is 7 years old

Step-by-step explanation:

Let

x ----> Marco's age

y ----> Paolo's age

we know that

x=y-8 ----> y=x+8 ----> equation A

xy=105 ----> equation B

substitute equation A in equation B

x(x+8)=105

x^2+8x-105=0

Solve the quadratic equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^2+8x-105=0

so

a=1\\b=8\\c=-105

substitute in the formula

x=\frac{-8(+/-)\sqrt{8^{2}-4(1)(-105)}} {2(1)}

x=\frac{-8(+/-)\sqrt{484}} {2}

x=\frac{-8(+/-)22} {2}

x=\frac{-8(+)22} {2}=7

x=\frac{-8(-)22} {2}=-15

Remember that the solution cannot be a negative number

so

The solution is x=7

therefore

Marco's age is 7 years old

4 0
3 years ago
7 - 3b-2(0 + 3 - 2b)
Naddika [18.5K]

Step-by-step explanation:

7 - 3b-2(0 + 3 - 2b)

To simplify the expression in the box, Fatua used

these steps:

Step 1:7 - 3b-2(3 - 3b)

Step 2:7 - 3-6-36-

Step 3: -13 - 66

Did Fatua calculate correctly? if nnot, in what step

did she make her FIRST mistake?

6 0
2 years ago
Read 2 more answers
Describe the behavior of the graph at the x-intercepts for the function f(x)=(2x-7)^7(x+3)^4. Identify each x-intercept and just
Shkiper50 [21]

Answer:

f(x)=(2x-7)^7(x+3)^4

When y=0, (2x-7)^7=0 and x=3.5 OR

(x+3)^4=0, and x=-3

Look at x=h or f(2)

That is 96-56-44+2 and it is not equal to 0. (x-2) is not a factor.

x^3-5x^2+6x-30

after trying 1,2, and 3, I tried 5

5/1===-5===6===-30

==1===0====6====30

(x^2-6) with no remainder

the factors are (x-5)(x^2+6)

the zeroes are 5, +/- i sqrt (6). Only one real 0.

hope this helps let me know in the comments if i'm wrong

7 0
2 years ago
Read 2 more answers
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