Answer:
2. a and b only.
Step-by-step explanation:
We can check all of the given conditions to see which is true and which false.
a. f(c)=0 for some c in (-2,2).
According to the intermediate value theorem this must be true, since the extreme values of the function are f(-2)=1 and f(2)=-1, so according to the theorem, there must be one x-value for which f(x)=0 (middle value between the extreme values) if the function is continuous.
b. the graph of f(-x)+x crosses the x-axis on (-2,2)
Let's test this condition, we will substitute x for the given values on the interval so we get:
f(-(-2))+(-2)
f(2)-2
-1-1=-3 lower limit
f(-2)+2
1+2=3 higher limit
according to these results, the graph must cross the x-axis at some point so the graph can move from f(x)=-3 to f(x)=3, so this must be true.
c. f(c)<1 for all c in (-2,2)
even though this might be true for some x-values of of the interval, there are some other points where this might not be the case. You can find one of those situations when finding f(-2)=1, which is a positive value of f(c), so this must be false.
The final answer is then 2. a and b only.
Answer: 5x² + 13x - 6 = 0
Step-by-step explanation:
Represent the roots with X i.e.
X = -3 ; X = 2/5
Moving the values of X over the equator we have;
X + 3 = 0 ; 5X - 2 = 0
Equating both equations to zero we can obtain;
(X + 3)(5X - 2) = 0
Opening the brackets we get;
5x² - 2x + 15x - 6 = 0
The result of the above equation gives;
5x² + 13x - 6 = 0
The statement of expressions is two terms and three factors.
<h3>
The statement and expressions:</h3>
According to the question, the statement that teaches us about expression is made up of two terms, each of which has three factors.
The ABC and DEF expressions define the expression of two terms, each of which comprises two elements.
As a result, the answer is two terms and three factors.
- The terms of the expressions are connected by mathematical signs like addition and subtraction.
- Variables are combined using multiplication signs to form the factor.
- The three components are found in each word.
- Looking at the first term ABC, we can see that it has three variables, a, b, and c, which is multiplied together.
Therefore, the answer is two terms and three factors.
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