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3 years ago

There are three times elephants compared to giraffes in the safari. If there is a total

Mathematics

1 answer:

Zinaida [17]3 years ago

7 0

Answer:

66 elephants

Step-by-step explanation:

88 divided by 4= 22

Therefore, there are 22 giraffes.

88-22=66. Therefore, there are 66 elephants. Hope this helps, feel free to ask for a more in depth explanation!

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Explain how you would use fraction bars to find the quotient of 10/12 ÷ 4/6. What is the quotient?

mylen [45]

(10/12) / (4/6)...when dividing with fractions, flip what u r dividing by, then multiply

10/12 * 6/4 = 10/8 which reduces to 5/4 or 1 1/4

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3 years ago

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Expand 3(-5q + 4). A.5q + 12 B.-15q + 4 C.-15q + 12 D. 5q + 12

Ksenya-84 [330]

_Award brainliest if helped!
(-5q * 3) + (4 *3 ) = -15q + 12
The answer is C.

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3 years ago

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What is the y-intercept for the graph of the equation 3x 5y = 15?

AysviL [449]

Answer:

15= 3×5y

15= 15y ( divide both side by 15)

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3 years ago

Please help! find the distance of AG if A (4,4) and G (-1,-1)

DochEvi [55]

${\qquad\qquad\huge\underline{{\sf Answer}}}$

Let's solve ~

By using distance formula :

$\qquad \sf \dashrightarrow \: \sqrt{(x_2 - x_1) {}^{2} + (y_2 - y_1) {}^{2} }$

$\qquad \sf \dashrightarrow \: \sqrt{(4 - ( - 1)) {}^{2} + (4 - ( - 1)) {}^{2} }$

$\qquad \sf \dashrightarrow \: \sqrt{(4 + 1) {}^{2} + (4 + 1) {}^{2} }$

$\qquad \sf \dashrightarrow \: \sqrt{2(5) {}^{2} }$

$\qquad \sf \dashrightarrow \: 5 \sqrt{2 }\: \: units$

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2 years ago

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Some shrubs have the useful ability to resprout from their roots after their tops are destroyed. Fire is a particular threat to

anyanavicka [17]

Answer:

The 99.5% confidence interval for the proportion of all shrubs of this species that will resprout after fire is (0, 0.5745).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 18, \pi = \frac{5}{18} = 0.2778$

99.5% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.9975$ , so $Z = 2.81$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2778 - 2.81\sqrt{\frac{0.2778*0.7222}{18}} = -0.01 = 0$

We cannot have a negative proportion, so we use 0.

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2778 + 2.81\sqrt{\frac{0.2778*0.7222}{18}} = 0.5745$

The 99.5% confidence interval for the proportion of all shrubs of this species that will resprout after fire is (0, 0.5745).

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3 years ago