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Wewaii [24]
3 years ago
9

Y - 0.8x = 0.5

Mathematics
1 answer:
Sveta_85 [38]3 years ago
7 0

Answer:

y=\frac{5+8x}{10} , x=x

Step-by-step explanation:

y-0.8x=0.5

y*10-0.8x*10=0.5*10

10y-8x=5

10y-8x+8x=5+8x

10y/10=5/10+8x/10

y=5+8x/10

5*5+8x/10-2.5

8x+5/2-2.5=4x

y=5+8x/10, x=x

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Step-by-step explanation:

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A rectangular box is to have a square base and a volume of 20 ft3. If the material for the base costs $0.35 per square foot, the
denpristay [2]

Answer:

Length = 2 ft

Width = 2 ft

Height = 5 ft

Step-by-step explanation:

Let the square base of the box has one side = x ft

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Cost to prepare the base = $0.35x²

Let the height of the box = y ft

Then the volume of the box = x²y ft³ = 20

y=\frac{20}{x^{3} } -----(1)

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Area of the sides = 4xy

Cost to prepare the sides of the box = $0.10 × 4xy

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Cost of the material to prepare the top = $0.15 per square feet

Cost to prepare the top = $0.15x²

Total cost of the box = 0.35x² + 0.40xy + 0.15x²

From equation (1),

Total cost C=0.35x^{2}+(0.40x)\times \frac{20}{x^{2} }+0.15x^{2}

C=0.35x^{2}+\frac{8}{x}+0.15x^{2}

C=0.5x^{2}+\frac{8}{x}

Now we take the derivative of C with respect to x and equate it to zero,

C'=0.5(2x)-\frac{8}{x^{2}} = 0

x-\frac{8}{x^{2}}=0

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x^{3}=8

x = 2 ft.

From equation (1),

(2)^{2}y=20

4y = 20

y = 5 ft

Therefore, Length and width of the box should be 2 ft and height of the box should be 5 ft for the minimum cost to construct the rectangular box.

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2 years ago
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ElenaW [278]
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The missing number in the arithmetic sequence 90, 83, ___, 69 is:
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The answer is 76

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