3 years ago

Someone Please HElp!!!!!3

Mathematics

1 answer:

iogann1982 [59]3 years ago

4 0

Answer: so wich line do we need to answer

Step-by-step explanation:

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Solve the System and write the solution as an ordered pair. <br><br> 3x+3y=6 <br> 5x-6y=15

Ugo [173]

$\\ \sf\longmapsto 3x+3y=6\dots(1)$

$\\ \sf\longmapsto 5x-6y=15\dots(2)$

Multiply eq(1) by 2 and eq(2) by 1

$\\ \sf\longmapsto 6x+6y=12$

$\\ \sf\longmapsto 5x-6y=15$

$\\ \sf\longmapsto 11x=27$

$\\ \sf\longmapsto x=\dfrac{27}{11}$

Now

Put in eq(1)

$\\ \sf\longmapsto 3\dfrac{27}{11}+3y=6$

$\\ \sf\longmapsto \dfrac{81}{11}+3y=6$

$\\ \sf\longmapsto 3y=6-\dfrac{81}{11}$

$\\ \sf\longmapsto 3y=\dfrac{66-81}{11}$

$\\ \sf\longmapsto 3y=\dfrac{15}{11}$

$\\ \sf\longmapsto y=\dfrac{15}{33}$

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