1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ilya [14]
3 years ago
6

Two competing sports equipment suppliers sell footballs at different prices. Supplier A charges $85 in shipping, and charges $2.

59 per football. Supplier B charges $50 shipped, and charges $4.29 per football. A school wants to buy 40 balls.
What is the equation for supplier A? Answer:

What is the equation for supplier B? Answer:

Which supplier has the lowest average cost per ball? Answer:
Mathematics
1 answer:
S_A_V [24]3 years ago
7 0
Supplier A: $188.6
Supplier B: $221.6

I hope I helped but I honestly have no idea if I did. Anyway sorry if I didn't. Good luck.
You might be interested in
Is it a function????
Troyanec [42]
Yes... according to what I know:)Let
me know if I’m wrong
7 0
3 years ago
Is this right? I’m unsure if I’m doing this correctly. Thanks
gogolik [260]
The answer is 24 as it's the smallest number given that is divisible by both 6 and 8.
4 0
3 years ago
Read 2 more answers
A boat travelling upstream goes 36 kilometers in 6 hours. If the return trip takes only 3 hours, what is the speed (in kilometer
mr_godi [17]
11 kilometer per hour
8 0
3 years ago
The local office supply store charges $0.08 per page to make photocopies. Lionel paid $20.00 for a set of copies. How many pages
Ivanshal [37]
Lionel had 250 pages copied

This is because 20/.08=250.
8 0
4 years ago
Read 2 more answers
A maker of a certain brand of low-fat cereal barsclaims that the average saturated fat content is 0.5gram. In a random sample of
finlep [7]

Answer:

t=\frac{0.475-0.5}{\frac{0.183}{\sqrt{8}}}=-0.386    

p_v =2*P(t_{(7)}  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is different from 0.5 at 5% of signficance.  So then the claim makes sense

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=0.475

The sample deviation calculated s=0.183

We need to conduct a hypothesis in order to check if the true mean is 0.5 or no, the system of hypothesis would be:  

Null hypothesis:\mu = 0.5  

Alternative hypothesis:\mu \neq 0.5  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{0.475-0.5}{\frac{0.183}{\sqrt{8}}}=-0.386    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=8-1=7  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(7)}  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is different from 0.5 at 5% of signficance.  So then the claim makes sense

4 0
3 years ago
Read 2 more answers
Other questions:
  • How many solutions are there to the following sysem of equations?
    5·1 answer
  • Find the values of x and y. Write your answer in simplest form.
    15·2 answers
  • What is the greatest common factor for 0.92?
    12·1 answer
  • I'm Stuck Please Help
    10·2 answers
  • Luis found two bicycles he likes. The price of the first bicycle is $73.59. The price of the second bicycle is $98.50. Estimate
    15·1 answer
  • What is the value of ?<br><br> 1. 22<br> 2. 882<br> 3. 220.5<br> 4. 21
    15·2 answers
  • Complete the inequality statement.
    12·1 answer
  • there are 1700 seats in a theatre. 40% of the tickets to a concert at the theatre are category 1 tickets and the rest are of oth
    8·1 answer
  • Which situation is a true statement about payment options?
    5·2 answers
  • What is the simplified form of the following expression: -(8n -5v)
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!