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levacccp [35]
3 years ago
6

Use the drawing tool(s) to form the correct answers on the provided number line.

Mathematics
2 answers:
vekshin13 years ago
7 0

Answer:

5 and -1

Step-by-step explanation:

nignag [31]3 years ago
7 0

Answer: 5 and -1

Step-by-step explanation:

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Suppose an angle α is drawn in standard position. In each case, use the information to determine what quadrant α is in.
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Since <span> sin(α) > 0 and cos(α) > 0
so </span><span>α is IN THE FIRST QUADRANT  (I)</span>
4 0
3 years ago
Cory brings five 1-gallon jugs of juice to server during parent night at his school. If the paper cups he is using for drinks ca
Svetlanka [38]

640 is your answer. 5 1-gallon jugs=640 fluid ounces.

4 0
3 years ago
What is the equation of the line that has an x-intercept of 2 and a y-intercept of 8?
Lunna [17]

Answer:

x-int: (2, 0)

y-int: (0,8)

(8-0)/(0-2)= 8/-2=  -4

y - 0 = -4(x - 2)

y = -4x + 8

Step-by-step explanation:

4 0
3 years ago
Evaluate the limit, if it exists.<br> lim (h - &gt; 0) ((-7 + h)^2 - 49) / h
baherus [9]

Expand everything in the limit:

\displaystyle\lim_{h\to0}\frac{(-7+h)^2-49}h=\lim_{h\to0}\frac{(49-14h+h^2)-49}h=\lim_{h\to0}\frac{h^2-14h}h

We have h approaching 0, and in particular h\neq0, so we can cancel a factor in the numerator and denominator:

\displaystyle\lim_{h\to0}\frac{h^2-14h}h=\lim_{h\to0}(h-14)=\boxed{-14}

Alternatively, if you already know about derivatives, consider the function f(x)=x^2, whose derivative is f'(x)=2x.

Using the limit definition, we have

f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h=\lim_{h\to0}\frac{(x+h)^2-x^2}h

which is exactly the original limit with x=-7. The derivative is 2x, so the value of the limit is, again, -14.

4 0
3 years ago
I need help on #14 please!
Morgarella [4.7K]
Yes your answer would be A 100000
6 0
3 years ago
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