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swat32
2 years ago
7

At the dog park on Monday, the ratio of small dogs to all dogs was three to seven. A total of 42 dogs were at the park. How many

small dogs were there?
Mathematics
1 answer:
faust18 [17]2 years ago
7 0

Answer:

18 small dogs

Step-by-step explanation:

Given the ratio  of small dogs to all dogs was 3:7

Total dogs that are there = 42 dogs

Number of small dogs there = ratio of small/ratio of all dogs * Total dogs

Number of small dogs there = 3/7 * 42

Number of small dogs there = 3 * 6

Number of small dogs there = 18

Hence there are 18 small dogs there

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Step-by-step explanation:

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2 years ago
Grant earns $5 for each magazine he sells.Write an equation in two variables showing the relationship between the number pf maga
slega [8]

Answer:

A=5m

Grant will make $60 from selling 12 magazines.

Step-by-step explanation:

Let m represent number of magazine sold and A represent amount of money earned.

We have been given that Grant earns $5 for each magazine he sells. So amount earned from m magazines would be 5 times m that is 5m dollars.

Now, we will equate total amount earned by Grant with A as:

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Therefore, our required equation would be A=5m.

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A=5(12)

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3 years ago
In an article regarding interracial dating and marriage recently appeared in a newspaper. Of 1719 randomly selected adults, 311
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Answer:

Step-by-step explanation:

Hello!

The parameter of interest in this exercise is the population proportion of Asians that would welcome a person of other races in their family. Using the race of the welcomed one as categorizer we can define 3 variables:

X₁: Number of Asians that would welcome a white person into their families.

X₂: Number of Asians that would welcome a Latino person into their families.

X₃: Number of Asians that would welcome a black person into their families.

Now since we are working with the population that identifies as "Asians" the sample size will be: n= 251

Since the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the variable distribution to normal.

Z_{1-\alpha /2}= Z_{0.975}= 1.965

1. 95% CI for Asians that would welcome a white person.

If 79% would welcome a white person, then the expected value is:

E(X)= n*p= 251*0.79= 198.29

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.79*0.21=41.6409

√V(X)= 6.45

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

198.29±1.965*6.45

[185.62;210.96]

With a 95% confidence level, you'd expect that the interval [185.62; 210.96] contains the number of Asian people that would welcome a White person in their family.

2. 95% CI for Asians that would welcome a Latino person.

If 71% would welcome a Latino person, then the expected value is:

E(X)= n*p= 251*0.71= 178.21

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.71*0.29= 51.6809

√V(X)= 7.19

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

178.21±1.965*7.19

[164.08; 192.34]

With a 95% confidence level, you'd expect that the interval [164.08; 192.34] contains the number of Asian people that would welcome a Latino person in their family.

3. 95% CI for Asians that would welcome a Black person.

If 66% would welcome a Black person, then the expected value is:

E(X)= n*p= 251*0.66= 165.66

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.66*0.34= 56.3244

√V(X)= 7.50

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

165.66±1.965*7.50

[150.92; 180.40]

With a 95% confidence level, you'd expect that the interval [150.92; 180.40] contains the number of Asian people that would welcome a Black person in their family.

I hope it helps!

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Answer:

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3 years ago
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Answer:

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Step-by-step explanation:

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