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swat32
3 years ago
7

At the dog park on Monday, the ratio of small dogs to all dogs was three to seven. A total of 42 dogs were at the park. How many

small dogs were there?
Mathematics
1 answer:
faust18 [17]3 years ago
7 0

Answer:

18 small dogs

Step-by-step explanation:

Given the ratio  of small dogs to all dogs was 3:7

Total dogs that are there = 42 dogs

Number of small dogs there = ratio of small/ratio of all dogs * Total dogs

Number of small dogs there = 3/7 * 42

Number of small dogs there = 3 * 6

Number of small dogs there = 18

Hence there are 18 small dogs there

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One integer is 3 more than 5 times another. The product is 54, what are the two integers?
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Step-by-step explanation:

Consider the provided information.

It is given that One integer is 3 more than 5 times another.

Let us consider the integer is <em>x</em>.

Then 3 more than 5 times of x is:

3+5x

The product of the provided two numbers is 54. i.e.

x(3+5x)=54

3x+5x^2=54

5x^2+3x-54=0

Use the formula of the quadratic equation:

For the equation ax^2+bx+c=0 the solutions are:

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

By comparing the obtained equation with the above equation, it can be concluded that <em>a</em> = 5, <em>b</em> = 3 and <em>c</em> = -54. Substitute the these values in the above formula.

x_{1,\:2}=\frac{-3\pm \sqrt{3^2-4\cdot \:5\left(-54\right)}}{2\cdot \:5}

x_{1,\:2}=\frac{-3\pm\sqrt{3^2+4\cdot \:5\cdot \:54}}{2\cdot \:5}

x_{1,\:2}=\frac{-3\pm\sqrt{1089}}{10}

x_{1,\:2}=\frac{-3\pm33}{10}

x_1=\frac{-3+33}{10} or x_2=\frac{-3-33}{10}

x_1=\frac{30}{10} or x_2=\frac{-36}{10}

x_1=3 or x_2=\frac{-18}{5}

As we have given that numbers are integer, therefore ignore x_2=\frac{-18}{5}

Thus, the value of <em>x</em> is 3 or one number is 3.

Then 3 more than 5 times of x is: 3 + 5(3) = 18.

Therefore, the two integers are 18 and 3.

5 0
3 years ago
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