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Nookie1986 [14]
3 years ago
14

Alex goes to the corner store to buy some candy bars and soft drinks. Soft drinks cost $2.00 each and each candy bar costs $1.00

. Alex can
spend no more than $8.00 and he can carry no more than 6 items back.
he can buy.
Let x represent the number of soft drinks Martin can buy and let y represent the number of candy bars he can buy. Write a system of inequalities to represent this situation.

Select all the coordinates that would be a solution.
A) (2, 2)
B) (1, 6)
C) (4, -4)
D) (3, 0)
E) (1, 3)
Mathematics
1 answer:
PIT_PIT [208]3 years ago
7 0
A b or c is the answer to your question
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Christina used 7.36 cups of flour to bake 0.8 cakes. How much flour, on average, did she put in each cake?
olga2289 [7]

Answer:

5.8 cups of flours

Step-by-step explanation:

5 0
3 years ago
Selmas class making a care package to give to victims of a natural disaster.Selma packs one box in 5 minutes and has already pac
bixtya [17]

Each of them need to work 105 minutes more in order to have packed the same number of boxes.

<u><em>Explanation</em></u>

Suppose, they need to work for x minutes more in order to have packed the same number of boxes.

Selma packs one box in 5 minutes and Trudy packs one box in 7 minutes.

So, the number of boxes packed by Selma in that x minutes =\frac{x}{5} and the number of boxes packed by Trudy in x minutes =\frac{x}{7}

Given that, Selma and Trudy have already packed 12 and 18 boxes.

Now if <u>each of them packed the same number of boxes</u>, then the equation will be......

12+\frac{x}{5}=18+\frac{x}{7}\\ \\ \frac{x}{5}-\frac{x}{7}= 18-12\\ \\ \frac{7x-5x}{35}=6\\ \\ \frac{2x}{35}=6\\ \\ 2x= 210\\ \\ x= \frac{210}{2}=105

So, each of them need to work 105 minutes more in order to have packed the same number of boxes.

6 0
3 years ago
Question is in the attachment
ruslelena [56]
Sorry I can’t see the pic
6 0
3 years ago
Use the x-intercept method to find all real solutions of the equation. -9x^3-72x^2+36=3x^3+x^2-3x+8
larisa86 [58]

-9x^3-72x^2+36=3x^3+x^2-3x+8                     Add 9x^3 to both sides.

-72x^2 + 36 = 3x^3 + 9x^3 + x^2 - 3x + 8       Add 72x^2 to both sides

36 = 12x^3 +   73x^2 - 3x + 8                           Subtract 36 from both sides.

0 = 12x^3 + 73x^2 - 3x - 28      

It does factor, but it is not very nice.

(x + 6.06)(x - 6.09)(x + 0.632)

If there is any kind of error please report it in a note below.

6 0
3 years ago
I answered it but I just need someone to answer just to make sure mine are right
Artemon [7]
<h2>The missing measures of the angles are:</h2>

m\angle 1= 60^{\circ}\\\\m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}

<u>Given</u>:

m\angle Z = 138^{\circ}

<em><u>Note the following:</u></em>

  • An equilateral triangle has all its three angles equal to each other. Each angle = 60^{\circ}.
  • This implies that, since \triangle WXY is equilateral, therefore, m\angle Y = m\angle XWY = m\angle XYW = 60^{\circ}

  • Base angles of an isosceles triangle are congruent to each other.
  • This implies that, since \triangle WZY is isosceles, therefore, m\angle 3 = \angle 5

Applying the above stated, let's find the measure of each angle:

  • Find m\angle 1

m\angle 1 = 60^{\circ} (an angle in an equilateral triangle equals 60 degrees)

  • Find m\angle 2

m\angle 2 = 60 - m \angle 3

m\angle 2 = 60 -\frac{1}{2}(180 - 138) (Note: \frac{1}{2}(180 - 138) = 1 $ base $ angle $ of $ \triangle WZY)

m\angle 2 = 60 -21\\\\m\angle 2 = 39^{\circ}

  • Find m\angle 3 and m\angle 5 (base angles of isosceles triangle WZY)

m\angle 3 =  \frac{1}{2}(180 - 138) (1 $ base $ angle $ of $ \triangle WZY)

m\angle 3 =  \frac{1}{2}(42) \\\\m\angle3 = 21^{\circ}

m\angle3 = m\angle 5 (base angles of isosceles triangle are congruent)

Therefore,

m\angle5 = 21^{\circ}

  • Find m\angle 4

m\angle 4 = 60 - m\angle 5

Substitute

m\angle 4 = 60 - 21\\\\m\angle 4 = 39^{\circ}

The missing measures of the angles are:

m\angle 1= 60^{\circ}\\\\ m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}

Learn more here:

brainly.com/question/2944195

5 0
3 years ago
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