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vovikov84 [41]
3 years ago
11

SOLVE FOR X PLEASEE HELP​

Mathematics
1 answer:
Ivenika [448]3 years ago
3 0
To solve this, you will have to set up your equation as fractions:

X is to 4 as 4 is to 4+3, or 7

X/4 = 4/7

You will then cross multiply

7x = 4•4
7x = 16

Divide.

X = 2.285714...

Round to the nearest hundredth.

2.29
You might be interested in
A/4=8/16 what is the missing number
NNADVOKAT [17]
A/4 = 8/16
cross multiply
(16)(A) = (8)(4)
16A = 32
A = 32/16
A = 2
5 0
3 years ago
Find an expression for the nth term -3 , 2 , 7, 12​
slavikrds [6]

Answer:

5n-8

Step-by-step explanation:

Because this is an arithmetic progression, there is simply an addend that is being added to every number. Because that is 5, the expression, for now, would be 5n. However, the progression does not start at 0, so we will have to subtract 3, and then it would be 5n - 3. We're still not at the answer; this is because the first term starts at 1, not 0. We will have to account for that, so subtract the coefficient, or 5, from the whole expression. That would be 5n - 8, and that would be the answer.

4 0
3 years ago
(3x²+4x-1) + (-2x²-3x+2)
Vedmedyk [2.9K]

Answer:

(3x²+4x-1) + (-2x²-3x+2)

3x²+4x-1 -2x²-3x+2

3x²-2x²+4x-3x-1+2

x²+x+1

5 0
3 years ago
Read 2 more answers
for every 300 kids in high school 2/3 of them take a language. What is the value of a number of students who dont take a languag
Anna [14]
All you have to do is divide 300 hundred by 3 and you get 100 students that don’t take a language So 200 students take language and 100 students don’t take language
3 0
3 years ago
Solve using the quadratic formula 3x^2+11x+5=0
storchak [24]

Answer:

3x^2 + 11x + 5 = 0 : x = \frac{-11 + \sqrt{61} }{6} , x = \frac{-11 - \sqrt{61} }{6}

Decimal:

(x = -0.53162..., x = -3.13504...)

Step-by-step explanation:

3x^2+11x+5=0

Solve with the quadratic formula:

For a quadratic equation of the form ax^2+bx+c=0 the solutions are:

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

For a=3,\:b=11,\:c=5:\quad x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}

x=\frac{-11 + \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 + \sqrt{61} }{6}

x=\frac{-11 - \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 - \sqrt{61} }{6}

The solutions to the quadratic equation are:

x=\frac{-11+\sqrt{61}}{6},\:x=\frac{-11-\sqrt{61}}{6}

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day! =)

8 0
4 years ago
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