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3 years ago

SOLVE FOR X PLEASEE HELP

Mathematics

1 answer:

Ivenika [448]3 years ago

3 0

To solve this, you will have to set up your equation as fractions:

X is to 4 as 4 is to 4+3, or 7

X/4 = 4/7

You will then cross multiply

7x = 4•4
7x = 16

Divide.

X = 2.285714...

Round to the nearest hundredth.

2.29

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What number is 5/8 of 56

navik [9.2K]

Answer:

Step-by-step explanation:

3 0

3 years ago

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Determine the value of x+3/8=2

zzz [600]

Answer:

x=13/8

Step-by-step explanation:

I took a picture of it instead of writing it out so its less confusing for you so click in the picture to get a full view to understand how to get 13/8.

7 0

3 years ago

Need help with this assignments

Mashcka [7]

Given values:-

P= 0.97

V= 2.85

R= 0.082

T= 295

n= ?

we have given formula,

PV=n RT

so,

n = PV/RT

$n = \frac{0.97 \times 2.85}{0.082 \times 295} \\ = \frac{2.7645}{24.19} \\ = 0.1142 \\ = 0.11$

0.11 is your answer.

3 0

3 years ago

Give the values of a, b, and c needed to write the equation's general form. 2/3(x - 4)(x + 5) = 1

ale4655 [162]

The first step is to write this equation into general form. The general form of an equation is:

ax^2 + bx + c = 0

To make this equation to general form, you have to simplify the equation first.

2/3(x-4) (x+5) = 1

2/3 (x^2 + 5x – 4x – 20) = 1

2/3(x^2 + x -20) = 1

2/3x^2 + 2/3x – 40/3 = 1

2/3x^2 + 2/3x – 40/3 – 1 = 0

2/3x^2 +2/3x – 43/3 = 0

Therefore, a = 2/3 ; b = 2/3 ; c = -43/3

4 0

3 years ago

Read 2 more answers

Suppose there are 50,000 deer in a forest

Korolek [52]

deer population p in n years is $p=50,000(1.2)^n$ .

<u>Step-by-step explanation:</u>

Here we have , Suppose there are 50,000 deer in a forest and the growth factor for the population is 1.2 per year. We need to Write an equation you could use to find the deer population p in n years. Let's find out:

We have , initially 50,000 deer in a forest . Every year population of deer increases by a factor of 1.2 , i.e. it increases exponentially depending on number of years .

For 1 year the population is increased by

⇒ $50,000(1.2)$

For 2 year the population is increased by

⇒ $50,000(1.2)^2$

So , For n year the population is increased by

⇒ $50,000(1.2)^n$

Therefore , deer population p in n years is $p=50,000(1.2)^n$ .

5 0

3 years ago

SOLVE FOR X PLEASEE HELP​

SOLVE FOR X PLEASEE HELP