Let T = total cost
Let 8c = total amount of children tickets
Let 12a = total amount of adult tickets
T = 8c + 12a
9514 1404 393
Answer:
a) E = 6500 -50d
b) 5000 kWh
c) the excess will last only 130 days, not enough for 5 months
Step-by-step explanation:
<u>Given</u>:
starting excess (E): 6500 kWh
usage: 50 kWh/day (d)
<u>Find</u>:
a) E(d)
b) E(30)
c) E(150)
<u>Solution</u>:
a) The exces is linearly decreasing with the number of days, so we have ...
E(d) = 6500 -50d
__
b) After 30 days, the excess remaining is ...
E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days
__
c) After 150 days, the excess remaining would be ...
E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system
The supply is not enough to last for 5 months.
Answer:
Each wand cost $0.056 which is below $50
Step-by-step explanation:
She bought 888 glitter wands for $50. This implies that each wand would cost:
$50/888 = $0.056
Each wand cost $0.056 which is far below the cost for glitter wands
Answer: The common difference is 8
Step-by-step explanation:
First Use the formula for the second to generate the first two numbers.
= 2^3n-2
Put in 1 for the first term and you will get 2 and the second term is 16 and to get from 2 to 16 you will multiply by 8.
