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2 years ago

Angles D and G are complementary. What statement must always be true about angles D and G?

Mathematics

1 answer:

nikklg [1K]2 years ago

4 0

Answer:

They will never intersect. I'm pretty sure that is right

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If a=4 and b=6 what is the answer <br> 5+(6a+10b)=

nika2105 [10]

Answer:

The answer to this problem is 89.

7 0

3 years ago

Read 2 more answers

Consider the implicit differential equation <img src="https://tex.z-dn.net/?f=%2849%20y%5E%7B3%7D%20%2B%2045%20xy%29%20dx%20%2B%

BaLLatris [955]

We're looking for an integrating factor $\mu(x,y)=x^py^q$ such that

$\mu\underbrace{(49y^3+45xy)}_M\,\mathrm dx+\mu\underbrace{(98xy^2+50x^2)}_N\,\mathrm dy=0$

is exact, which would require that

$(\mu M)_y=(\mu N)_x$
$(49x^py^{q+3}+45x^{p+1}y^{q+1})_y=(98x^{p+1}y^{q+2}+50x^{p+2}y^q)_x$
$49(q+3)x^py^{q+2}+45(q+1)x^{p+1}y^q=98(p+1)x^py^{q+2}+50(p+2)x^{p+1}y^q$
$\implies\begin{cases}49(q+3)=98(p+1)\\45(q+1)=50(p+2)\end{cases}\implies p=\dfrac52,q=4$

You can verify that $(\mu M)_y=(\mu N)_x$ if you'd like. With the ODE now exact, we have a solution $F(x,y)=C$ such that

$F_x=\mu M$
$F=\displaystyle\int(49y^3+45xy)x^{5/2}y^4\,\mathrm dx$
$F=10x^{9/2}y^5+14x^{7/2}y^7+f(y)$

$F_y=\mu N$
$50x^{9/2}y^4+98x^{7/2}y^6+f'(y)=98x^{7/2}y^2+50x^{9/2}y^4$
$f'(y)=0$
$\implies f(y)=C$

and so the general solution is

$F(x,y)=10x^{9/2}y^5+14x^{7/2}y^7=C$

8 0

3 years ago

Given a linear equation in the form y=mx+b, what are the values of the slope and y-intercept of the equation?(1 point) The slope

slamgirl [31]

Answer:

The slope is m, and the y-intercept is b.

Step-by-step explanation:

What ever is attached to the x is the slope. The y-intercept is the b because it has a 0 on the x axis and a number on the y axis.

7 0

3 years ago

Find the slope of the line passing through the points (-9, 3) and (7, -7).

Viktor [21]

Answer:

-10/16

Step-by-step explanation:

-7z3=-10 and 7-(-9)=16

6 0

2 years ago

Find the product of (3x -2) (3x + 5)

Mashcka [7]

Do I answer this in slope intercept form?

6 0

2 years ago