The expression θ = - 50° ± i · 360°, 
represents the family of all angles <em>coterminal</em> with - 50° angle.
<h3>What is the family of angles coterminal to a given one?</h3>
Two angles are <em>coterminal</em> if and only if their end have the <em>same</em> direction. Two <em>consecutive coterminal</em> angles have a difference of 360°. Then, we can derive an expression representing the family of all angles <em>coterminal</em> to - 50° angle.
θ = - 50° ± i · 360°,
The expression θ = - 50° ± i · 360°, represents the family of all angles <em>coterminal</em> with - 50° angle.
<h3>Remark</h3>
The statement is incomplete and complete form cannot be reconstructed. Thus, we modify the statement to determine the family of angles coterminal to - 50° angle.
To learn more on coterminal angles: brainly.com/question/23093580
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Answer:
Step-by-step explanation:
With a factor of (t - 1) we know that zero (ground level) is reached at 1 second from an initial height of (0 - 1)(0 - 1)(0 - 11)(0 - 13)/3 = -1•-1•-11•-13 / 3 = 47⅔ meters at t = 0
As we have <em>two </em>factors of (t - 1) we know the track does not go underground at t = 1, but rises again.
At t = 11 seconds, the car has again returned to ground level, but as we only have a single factor of (t - 11) the car plunges below ground level and returns to above ground level at t = 13 seconds due to the single factor of (t - 13)
we can estimate that the car is the deepest below ground level halfway between 11 and 13 s, so at t = 12. At that time, the depth will be about (12 - 1)(12 - 1)(12 - 11)(12 - 13) / 3 = -(11²/3) = - 40⅓ m.
we can estimate that the car is the highest above ground level halfway between 1 and 11 s, so at t = 6s. At that time, the height will be about (6 - 1)(6 - 1)(6 - 11)(6 - 13) / 3 = 5²•-5•-7 / 3 = 291⅔ m.
It's obvious that the roller coaster car had significant initial velocity at t = 0 to achieve that altitude from an initial height of 47⅔ m
