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4 years ago

Please help me with this question !!!!

Mathematics

1 answer:

AlekseyPX4 years ago

4 0

The distance of DC=HG,4.47; distance of CB=GF, 2.23; distance of BA=FE, 2.23; distance of AD=EH, 3.16

Answer:All sides are congruent so the shapes are congruent

Hope this helps :)

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WORTH 20 POINTS HELP

vfiekz [6]

Below represents the proof that the quadrilateral QRST is a parallelogram

<h3>How to prove that QRST is a parallelogram?</h3>

The coordinates are given as:

Q = (-1,-1)

R = (2,9)

S = (-4,5)

T = (-7,-5)

Calculate the length of each side using:

$d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}$

So, we have:

$QR = \sqrt{(-1 - 2)^2 + (-1 -9)^2} = \sqrt{109}$

$RS = \sqrt{(-4 - 2)^2 + (5 - 9)^2} = \sqrt{52}$

$ST = \sqrt{(-7 + 4)^2 + (-5 - 5)^2} = \sqrt{109}$

$TQ = \sqrt{(-7 + 1)^2 + (-5 + 1)^2} = \sqrt{52}$

The above computations show that opposite sides are equal.

Next, we determine the slope of each side using:

$m = \frac{y_2 -y_1}{x_2 -x_1}$

So, we have:

$QR = \frac{9 + 1}{2 + 3} = \frac{10}3$

$RS = \frac{5-9}{-4 - 2} = \frac{2}3$

$ST = \frac{5+5}{-4 + 7} = \frac{10}3$

$TQ = \frac{-5+1}{-7 + 1} = \frac{2}3$

The above computations show that opposite sides are parallel, because they have equal slope

Hence, the quadrilateral QRST is a parallelogram

Read more about parallelograms at:

brainly.com/question/3050890

#SPJ1

6 0

2 years ago

For what value of c does x^2−2x−c=4 have exactly one real solution?<br> PLEASE HELP!!!!!!!

Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

$x^2-2x-(c+4)=0$ .

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic $ax^2+bx+d$ , the discriminant is $\sqrt{b^2-4ad}$ .

(The discriminant is more commonly known as $\sqrt{b^2-4ac}$ , but I changed the variable since we already have a $c$ in the quadratic given.)

In the quadratic above, we have $a=1$ , $b=-2$ , and $d=-(c+4)$ . Plugging this into the formula for the discriminant, we have

$\sqrt{(-2)^2-4(1)(-(c+4))$ .

Using the distributive property to expand and simplifying, the expression becomes

$\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.$

Setting the discriminant equal to 0 gives

$2\sqrt{c+5}=0$ .

We can then solve the equation as usual: first, divide by 2 on both sides:

$\sqrt{c+5}=0$ .

Squaring both sides gives

$c+5=0$ ,

and subtracting 5 from both sides, we have

$\boxed{c=-5}.$

3 0

2 years ago

Factor completely and then place the factors in the proper location on the grid. 4y 2 + 25y + 6

astraxan [27]

(4y + 1)(y + 6)
I don't know what you mean by proper location
It shouldn't matter what order the factors are in.

8 0

3 years ago

What is Derricka's goal, in miles, for the total distance she will swim on Monday, Tuesday, and Wednesday? Show your work.

denpristay [2]

Answer:

there is no backgroung information?

Step-by-step explanation:

3 0

3 years ago

Select the sets that are not functions.

Kaylis [27]

Answer:

D,E are not functions

Step-by-step explanation:

A function is a relation in which every input has not more than one output.But the output of the inputs may be same.Here in D the input 1 has 4 different outputs as 1,2,3,4.So its not a function.Similarly in E 6 has 2 outputs as 2 and -1.For remaining sets the inputs has only one output.so they are functions.

7 0

3 years ago