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ANTONII [103]
3 years ago
6

Please find the missing angle

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
8 0
360 degrees in a circle

360 degrees minus 90 degrees (the right angle of the square) = 270 degrees

270 degrees divided by 2 = 135 degrees

f = 135 degrees
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Can anyone help me set up a system of equations for these problems??
statuscvo [17]

Answer:

L = the length of the field

W = the width of the field

The First Question:

The system is: L - 12 = w

                         2L + 2W = 76

Plug in L - 12 for W and you will get

2L + 2L - 24 = 76

4L -24 = 76

4L = 100

L = 25

To find W do L - 12 = w

25 - 12 = w

w = 13

8 0
2 years ago
Find the area of the right triangle △DEF with the points D (0, 0), E (1, 1), and F.
Tems11 [23]

Answer:

The area of the triangle is  \sqrt{3}

Step-by-step explanation:

Given:

Coordinates D (0, 0), E (1, 1)

Angle  ∠DEF = 60°

△DEF is a Right triangle

To Find:

The area of the triangle

Solution:

The area of the triangle is  = \frac{1}{2}(base \times height)

Here the base is Distance between D and E

calculation the distance using the distance formula, we get

DE  = \sqrt{(0-1)^2 + (0-1)^2}

DE =\sqrt{(-1) ^2 + (-1)^2

DE = \sqrt{1+1}

DE = \sqrt{2}

Base = \sqrt{2}

Height is DF

DF =tan(60^{\circ}) \times DE

DF = \sqrt{3} \times DE

DF = \sqrt{3} \times\sqrt{2}

Now, the area of the triangle is

= \frac{1}{2}({\sqrt{2})(\sqrt{3} \times \sqrt{2})

=\frac{1}{2}({\sqrt{2})(\sqrt{3} \sqrt{2})

=\frac{1}{2}(2\sqrt{3} )

=\sqrt{3}

6 0
3 years ago
What is the equation of the following line?​
Irina18 [472]

Answer:

Y=5x

Step-by-step explanation:

slope equation

<u>y-y1</u>

x-x1

10-0=10

2-0=2

10/2=5

7 0
2 years ago
COSO ---
Vsevolod [243]

Answer:

• zero: -4, -4/3, 7

• positive: -4 < x < -4/3 . . . or 7 < x

• negative: x < -4 . . . or -4/3 < x < 7

Step-by-step explanation:

Zeros of the function are at x=-4, -4/3, +7. These are the values that make each of the individual factors be zero. For example, x-7=0 when x=7.

The function will be negative for x-values left of an odd number of zeros. It will be positive for x-values left of an even number of zeros (including left of no zeros, which is to say right of all zeros). This is because the sign of the factor giving rise to the zero changes for x-values on either side of that zero. (This is not true for zeros with even multiplicity, as the sign does not change at those.)

3 0
3 years ago
HELP TIMED BRAINLIST
lesya692 [45]

Answer:

it's D

Step-by-step explanation:

You use distribute property, then add all like terms

3 0
2 years ago
Read 2 more answers
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