Answer:
The velocity of the car after the collision is -5.36 m/s
Step-by-step explanation:
An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.
let the following:
m₁ = mass of the car = 1400 kg
m₂ = mass of the truck = 3200 kg
u₁ = velocity of the car before collision = 13.7 m/s
u₂ = velocity of the truck before collision = 0 m/s
v₁ = velocity of the car after collision
v₂ = velocity of the truck after collision
v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)
= [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)
= - 5.36 m/s
So, <u>the velocity of the car after the collision is -5.36 m/s</u>
6 x -2 = -12
-12 = 3, -4
y = 6x^2 + 3x - 4x - 2
y = 3x(2x + 1) - 2(2x + 1)
(2x + 1) (3x - 2) = 0
2x = -1, 3x = 2
x = -1/2, 2/3
pls give brainliest im trying to level up :))
<span>So the equation: (x+8) divided by 2 =24</span>
