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Andrews [41]
3 years ago
13

From 10:00 am to noon, the rise in temperature is 4 degrees C, and from 3:00 pm to 5:00 pm, the fall in temperature is 6 degrees

C. What is the average rate of: a) The rise in temperature per hour? b) The fall in temperature per hour?
Mathematics
1 answer:
lyudmila [28]3 years ago
3 0

Answer:

(a) 2 degree celsius per hour

(b) 3 degree celsius per hour.

Step-by-step explanation:

From the question,

(a) Avearge rate of rise in temperature per hour(T') = Rise in temperature(T)/Time required for the rise(t).

T' = T/t.................... Euqation 1

Rise in temperature (T) = 4 degree celsius, t = 10.00 am to noon = 2 hours.

Substitute into equation 1

T' = 4/2

T' = 2 degree celsius per hour.

(b) Also,

Average rate of fall in temperature per hour (T') = Fall in temperature (T)/Time(t)

T' = T/t

Given: T = 6 degree celsius, t = 3:00 pm to 5:00 pm = 2 hours

T' = 6/2

T' = 3 degree celsius per hour

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Read more on slope of a tangent here: brainly.com/question/26015157

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