Can someone help me with this?

Mathematics

1 answer:

Alexeev081 [22]3 years ago

8 0

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the areas,

Area of a rectangle = length * width.

hence, l = 11 and w = 4

hence, 4*11 = 44 square units.

Area = 44 sq. units

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A rectangle has a length of 34 inches less than 5 times it’s width. If the area of the rectangle is 867 square inches, find the

pshichka [43]

Length of the rectangle is 51 inches

Solution:

Given that

Length of the rectangle in 34 miles less than 5 times its width

Area of rectangle = 867 square inches

Need to determine length of the rectangle.

Let assume width of the rectangle be represented by variable x.

So 5 times width of the rectangle =5x

34 inches less than 5 times width of the rectangle = 5x – 34

As Length of the rectangle in 34 miles less than 5 times its width

=> Length of the rectangle = 5x – 34

The formula for rectangle is given as:

$\text { area of rectangle }=length \times width$

As given that Area of rectangle = 867 square inches

$\begin{array}{l}{=>867=(5 x-34) \times(x)} \\\\ {=>5 x^{2}-34 x-867=0}\end{array}$

On solving quadratic equation by using quadratic formula

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case a = 5, b = -34 and c = -867

On substituting value of a, b and c in quadratic formula we get

$\begin{array}{l}{x=\frac{-(-34) \pm \sqrt{(-34)^{2}-4 \times 5 \times(-867)}}{2 \times 5}} \\\\ {=>x=\frac{34 \pm \sqrt{18496}}{10}=\frac{34+136}{10}} \\\\ {=>x=\frac{34+136}{10}=17 \text { or } x=\frac{34-136}{10}=-10.2}\end{array}$

Since x represents width, it cannot be negative, so x = 17

Length of the rectangle = 5x – 34 = 5(17) – 34 = 51

Hence length of the rectangle is 51 inches

5 0

3 years ago

No body helped me the last time so I’m posting it again I really need help with this

PIT_PIT [208]

B is equal to 154 degrees. we know this cause half of the circle equals 180 and if you subtract a (26) from 180 you get 154

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3 years ago

What's the quotient of I? 5+5i divided by 2+I

sladkih [1.3K]

$if\ "i"\ is\ the\ imaginary\ unit:\sqrt{-1}=i\Rightarrow i^2=-1\\\\then\\\\\frac{5+5i}{2+i}=\frac{5+5i}{2+i}\cdot\frac{2-i}{2-i}=\frac{10-5i+10i+5i^2}{2^2-i^2}=\frac{10+5i-5}{4+1}=\frac{5+5i}{5}=\boxed{1+i}$