Question

Does anyone know what the formula is? ​

Answer 1

Answer:

x is around 29.5

Step-by-step explanation:

Let's just use the law of cosines.

$c^2 = a^2 + b^2 - 2ab\cos\angle (ab)\\\\6.9^2 = 5.3^2 + 11^2 - 2\cdot5.3\cdot11\cdot \cos x^{\circ}\\47.61 = 28.09 + 121 - 116.6\cdot\cos x^{\circ}\\~\\cos x^{\circ} = \frac{149.09 - 47.61}{116.6} = \frac{101.48}{116.6}\\~\\x^{\circ} = \arccos\frac{101.48}{116.6}\\~\\x^{\circ} \approx 29.5^\circ$

Answer 2

Answer:

29.50 degrees to the nearest hundredth.

Step-by-step explanation:

First we can find the measure of < CGB by using the Cosine Rule:

cos <CGB = (11^2 - 5.3^2 - 6.9^2) / (-2 * 5.3 * 6.9)

= -0.61936

So m < CGB = 128.27 degrees.

Now we can find the measure of x by using the Sine Rule:

11 / sin 128.27 = 6.9  / sin x

sin x =  6.9 * sin 128.27 / 11

= 0.49248

x = 29.5035 degrees