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IrinaK [193]
3 years ago
11

Tienen capacidad de fijar enerjgia luminosa utilizando agua y co2 para transformarlo en carbohidratos

Chemistry
1 answer:
Cloud [144]3 years ago
7 0

Answer:

las plantas

Explanation:

Las plantas son los seres vivos capaces de transformar energía luminosa utilizando agua y dióxido de carbono (CO₂) en energía química en forma de moléculas llamadas carbohidratos. El proceso a través del cual realizan esto se denomina fotosíntesis, y para ello requieren un pigmento de color verde denominado clorofila, el cual es necesario para captar la energía luminosa proveniente del Sol.

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Mixing colored lights & mixing colored paints. The primary colors of light are also known as the additive colors, because, when you add these three colors of light (red, green and blue) your brain perceives white light. The primary colors of paints, however, are known as subtractive colors.

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Read 2 more answers
What is the total energy change for the following reaction:CO+H2O-CO2+H2
Alekssandra [29.7K]

Answer:

\large \boxed{\text{-41.2 kJ/mol}}

Explanation:

Balanced equation:    CO(g) + H₂O(g) ⟶ CO₂(g) + H₂(g)

We can calculate the enthalpy change of a reaction by using the enthalpies of formation of reactants and products

\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)

(a) Enthalpies of formation of reactants and products

\begin{array}{cc}\textbf{Substance} & \textbf{$\Delta_{\text{f}}$H/(kJ/mol}) \\\text{CO(g)} & -110.5 \\\text{H$_{2}$O} & -241.8\\\text{CO$_{2}$(g)} & -393.5 \\\text{H$_{2}$(g)} & 0 \\\end{array}

(b) Total enthalpies of reactants and products

\begin{array}{ccr}\textbf{Substance} & \textbf{Contribution)/(kJ/mol})&\textbf{Sum} \\\text{CO(g)} & -110.5& -110.5 \\\text{H$_{2}$O(g)} &-241.8& -241.8\\\textbf{Total}&\textbf{for reactants} &\mathbf{ -352.3}\\&&\\\text{CO}_{2}(g) & -393.5&-393.5 \\\text{H}_{2} & 0 & 0\\\textbf{Total}&\textbf{for products} & \mathbf{-393.5}\end{array}

(c) Enthalpy of reaction \Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)= \text{-393.5 kJ/mol - (-352.3 kJ/mol}\\= \text{-393.5 kJ/mol + 352.3 kJ/mol} = \textbf{-41.2 kJ/mol}\\ \text{The total enthalpy change is $\large \boxed{\textbf{-41.2 kJ/mol}}$}

4 0
3 years ago
How does the volume of gas particles compare to the volume of the space between gas particles?
Ugo [173]
Gas particles are small and the total volume occupied by gas molecules is negligible relative to the total volume of their container. ... The average kinetic energy of gas particles is proportional to the absolute temperature of the gas, and all gases at the same temperature have the same average kinetic energy

Hope this helps
3 0
3 years ago
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