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sweet-ann [11.9K]
3 years ago
9

Two ballpoint pens are selected at random from a box that contains3 blue pens, 2 red pensand 3 green pens. If X is the number of

blue pens
Mathematics
1 answer:
EastWind [94]3 years ago
8 0

Answer:  3/(28) ≈ 10.7%

<u>Step-by-step explanation:</u>

3 blue + 2 red + 3 green = 8 total pens

   First pick    and           Second pick

 \dfrac{3\ blue\ pens}{8\ total\ pens}\quad \times \quad \dfrac{2\ remaining\ blue\ pens}{7\ remaining\ total\ pens}\quad =\large\boxed{\dfrac{3}{28}}  

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5. 40 = -1/3(9x + 30)+ 2
Natali5045456 [20]

Answer:

x = -16

Step-by-step explanation:

-1/3 * 9x = -3x

-1/3 * 30 = -10

-10 + 2 = -8

40 = -3x - 8

+8          +8

48 = -3x

---     ----

-3    -3

-16 = x

x = -16

~ Zoe

6 0
2 years ago
Mr. Lassie goes out to eat with his family. Their dinner costs $144. Mr. Lassie is going to leave a 25% tip because the service
Dmitry_Shevchenko [17]

Answer:

$180

Step-by-step explanation:

25% ->0.25

144(0.25)=36

36+144=180

4 0
2 years ago
Select the correct answer from each drop-down menu. Which system of equations is represented by this graph? Graph shows system o
AleksandrR [38]

The equation of the line going through (-6, 0) and (0, -3) is y = -(1/2)x - 3

The equation of the line going through (0, 3) and (-4, -5) is y = 2x + 3

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

The equation of the line going through (-6, 0) and (0, -3) is:

y - 0 = [(-3 - 0) / (0- (-6)](x - (-6))

y = -(1/2)x - 3

The equation of the line going through (0, 3) and (-4, -5) is:

y - 3 = [(-5 - 3) / (-4 - 0)](x - 0)

y = 2x + 3

Find out more on equation at: brainly.com/question/2972832

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7 0
2 years ago
Wright the expression 6a - 2 (a-1) in simplest form
vovikov84 [41]
6a-2(a-1)
6a-2a-2
4a-2
I think it is 4a-2
6 0
3 years ago
If (ax^2 + 3x + 2b) - (5x^2+bx-3c)=3x^2-9, what is the value of A + B + C?
Rina8888 [55]

Answer:

We have the equation:

(ax^2 + 3x + 2b) - (5x^2+bx-3c)=  3x^2 - 9

First, move all to the left side.

(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0

Now let's group togheter terms with the same power of x.

(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.

This must be zero for all the values of x, then the things inside each parenthesis must be zero.

1)

a - 5 - 3 = 0

a = 3 + 5 = 8.

2)

3 - b = 0

b = 3.

3)

2b + 3c + 9 = 0

2*3 + 3c + 9 = 0

3c = -6 - 9 = -15

c = -15/3 = -5

Then we have:

a = 8, b = 3, c = -5

a + b + c = 8 + 3 - 5 = 6

8 0
3 years ago
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