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never [62]
1 year ago
14

When a die is rolled, what is the theoretical probability that number five will be rolled? ​

Mathematics
1 answer:
Marta_Voda [28]1 year ago
7 0

Answer: 1/6

Step-by-step explanation: there is 6 faces on a standard die, one of them is 5.

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If s and t are integers greater than 1 and each is a factor of the integer n, which of the following must be a factor of n^{st}
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E) 1 and 2

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We are given that there are two integers (s and t) and they are factors of another integer (n). For example if s = 3 and t = 2, we can have n = 6.

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For the first condition: s^t = 3^2 is a factor of (2^6)(3^6)

For the second condition: (st)^2 = (3*2)^2 = 6^2 is a factor of 6^6

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<em>a</em><em>)</em><em> </em><em>Four </em><em>thousand</em><em> </em><em>five </em><em>hundred</em><em> </em><em>thirty-six.</em>

<em>b)</em><em> </em><em>arrange </em><em>in </em><em>descending</em><em> </em><em>order</em>

<em>3</em><em>4</em><em>5</em><em>6</em><em>.</em>

<em>c)</em><em> </em><em>since </em><em>we </em><em>have </em><em>to </em><em>make </em><em>odd </em><em>number</em><em> </em><em>therefore</em><em> </em><em>once </em><em>digit</em><em> </em><em>will </em><em>be </em><em>odd </em><em>,</em><em> </em><em>3</em><em> </em><em>(</em><em> </em><em>or </em><em>5</em><em> </em><em>too </em><em>)</em>

<em>so,</em><em> </em><em>the </em><em>number</em><em> </em><em>is </em><em>6</em><em>5</em><em>4</em><em>3</em><em>.</em>

<em>hope </em><em>this</em><em> answer</em><em> helps</em><em> you</em><em> dear</em><em>!</em>

4 0
2 years ago
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