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3 years ago

What is 5ax + c = 8.5?

Mathematics

2 answers:

Ulleksa [173]3 years ago

7 0

Step-by-step explanation:

5ax + c = 8.5

5ax=8.5-c

x= (8.5-c)/5a

lara31 [8.8K]3 years ago

3 0

Answer:

the answer of this question is i dont know

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What is the completely factored form of the following expression<br> 6b2+5b-4

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3 years ago

Solve for all values of x in simplest form. 9-4|3+5x|=5

Zinaida [17]

Answer:

$x=-2/5\text{ or } x=-4/5$

Step-by-step explanation:

So we have the equation:

$9-4|3+5x|=5$

First, subtract 9 from both sides:

$-4|3+5x|=-4$

Divide both sides by -4:

$|3+5x|=1$

Definition of Absolute Value:

$3+5x=1\text{ or } 3+5x=-1$

Subtract 3 from both sides:

$5x=-2\text{ or } 5x=-4$

Divide both sides by 5:

$x=-2/5\text{ or } x=-4/5$

And we're done!

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3 years ago

Read 2 more answers

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3 years ago

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3 years ago

Solving separable differential equation DY over DX equals xy+3x-y-3/xy-2x+4y-8

Ivanshal [37]

It looks like the differential equation is

$\dfrac{dy}{dx} = \dfrac{xy + 3x - y - 3}{xy - 2x + 4y - 8}$

Factorize the right side by grouping.

$xy + 3x - y - 3 = x (y + 3) - (y + 3) = (x - 1) (y + 3)$

$xy - 2x + 4y - 8 = x (y - 2) + 4 (y - 2) = (x + 4) (y - 2)$

Now we can separate variables as

$\dfrac{dy}{dx} = \dfrac{(x-1)(y+3)}{(x+4)(y-2)} \implies \dfrac{y-2}{y+3} \, dy = \dfrac{x-1}{x+4} \, dx$

Integrate both sides.

$\displaystyle \int \frac{y-2}{y+3} \, dy = \int \frac{x-1}{x+4} \, dx$

$\displaystyle \int \left(1 - \frac5{y+3}\right) \, dy = \int \left(1 - \frac5{x + 4}\right) \, dx$

$\implies \boxed{y - 5 \ln|y + 3| = x - 5 \ln|x + 4| + C}$

You could go on to solve for $y$ explicitly as a function of $x$ , but that involves a special function called the "product logarithm" or "Lambert W" function, which is probably beyond your scope.

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2 years ago