With $2.16, Albert can buy:
2 pencils
OR
6 markers
Therefore, Albert can buy 4 more markers than he can pencils.
Hey there!
For this problem you need to replace x with 45
So the new problem is 2(45)+4
2 x 45 = 90
then 90+4 = 94
Your answer is 94
Hope I was able to help!
Answer:
Step-by-step explanation:
Given that a hat contains n coins, f of which are fair, and b of which are biased to land heads with probability 2/3
A coin is drawn from the hat and tossed twice. The first time it lands heads, and the second time it lands tails.
There are two possibilities. Either fair coin is drawn or biased is drawn.
Let A1 = I coin drawn and A2 = II coin is drawn.
B= the first toss lands head and II tails.
Prob it is a fair coin =
10 pencils will be defective
4/1,000 = 10/2,500 1,000 x 2.5 = 2,500
4 x 2.5 = 10
Hope it helps!!!!!!
Answer:
(6x + 2) + 40 = 90
Step-by-step explanation: