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mrs_skeptik [129]
2 years ago
14

In d Mohit deposited 2 12000 be depos would ( money 900. The interest B 800 o O 1800​

Mathematics
1 answer:
jeka57 [31]2 years ago
5 0

I need the answer too lol, does anyone knows it ?

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I need help on this problem
chubhunter [2.5K]
The value of x
3x°+46°+(2x-1°)=180°(angle sum of △)
5x+45=180°
5x=180°-45
x=135÷5
x=27
x is 27

put x into angle B,we have
2(27)-1
=53

thus angleB is 53°

hope it helps c:
6 0
4 years ago
Read 2 more answers
What is the equation of a line perpendicular to the line y=(4/9)x-2 that passes through the point (4,3)?
Hoochie [10]
<span>y=(4/9)x-2
This is in slope intercept form (y=mx+b), where m is the slope. 
A perpendicular line will have the opposite reciprocal of the slope.
So if the slope here is 4/9, then the perpendicular line's slope will be -9/4.

Now that you have the slope (-9/4) and a point (4, 3), you can use the point-slope formula to find the equation.
y - y</span>₁ = m(x - x₁)
y - 3 = (-9/4)(x - 4)
y - 3 = (-9/4)x + 9
y = (-9/4)x + 12

So the answer will be:
C. <span>y= -(9/4)x+12</span>
3 0
4 years ago
Pyramid a has a lateral edge of 10 and a height of 8. Pyramid B has a lateral edges of length 15 and height 12. Both A and B are
melamori03 [73]

Answer:

Pyramid A is 10*10*8/3 which is 800/3 and Pyramid B is 15*15*12/3 which is 2700/3, so the ratio would simply be 8:27 uwu

Step-by-step explanation:

3 0
3 years ago
Find radius of a hemisphere given volume of 144 cm³
marysya [2.9K]

Answer:

The radius is 4.097396898

Step-by-step explanation:

A hemisphere is 1/2 of a sphere so the volume is 1/2 of the volume

V = 1/2 ( 4/3 pi r^3)

   = 2/3 pi r^3

144 = 2/3 pi r^3

Multiply each side by 3/2

3/2 *144 = 3/2 * 2/3 pi r^3

216 = pi r^3

Divide each side by pi

216/ pi =   pi r^3/pi

68.78980892 = r^3

Take the cube root of each side

(68.78980892 )^1/3= (r^3)^1/3

4.097396898 = r

The radius is 4.097396898

8 0
3 years ago
(How to calculate (-2,8) and (1,6) that =-2/3
Pavel [41]
(6-8)/(1+2)= -2/3 the answer to the question
3 0
3 years ago
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