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solong [7]
4 years ago
11

mouse scurries across your kitchen floor at 2.0 feet per second. How many miles can the mouse travel in 1.5 hours (rounded to th

e nearest tenth)?
Mathematics
2 answers:
ad-work [718]4 years ago
6 0
2.0 times 60= 120 feet per minute
120 times 90= 10,800.0 feet
10,800 times 0.000189= about 2.0 miles
Lera25 [3.4K]4 years ago
3 0

Answer: the mouse can travel a distance of 2.05 miles in 1.5 hours

Step-by-step explanation:

The speed of the mouse is 2ft/s

We want to know how many miles will the mouse travel in 1.5 hours, so the first steep is change the units:

1 mile = 5280 feet

so 2 feet =  (2/5280) miles

Then the speed is:

s = (2/5280) milles per second.

now, in one hour and half, we have 90 minutes, and a minute has 60 seconds, so 1.5 houes is equivalent to:

90*60s = 5400s

So the distance that the mouse moves in 1.5 hours in miles is:

D = (2/5280)*5400  miles = 2.05 miles

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Solve this equation<br> 16(1/4x-1/2)&gt;24-2x
jekas [21]

Answer:

x>14

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

−4>−2x+24

Step 2: Flip the equation.

−2x+24<−4

Step 3: Subtract 24 from both sides.

−2x+24−24<−4−24

−2x<−28

Step 4: Divide both sides by -2.

−2x−2<−28−2

x>14

5 0
3 years ago
Read 2 more answers
What’s the slope for this graphed?<br> A.1/2<br> B.-2<br> C.2<br> D.-3
Scorpion4ik [409]

Answer:

the answer is just 2

Step-by-step explanation:

start at the -3 and move right 3 and up 6 this is a inclined line so the answer will be positive the fraction put the numbers into a rise over run fraction which will be 6/3 which will reduce to 2/1 which is 2.

6 0
3 years ago
To help consumers assess the risks they are taking, the Food and Drug Administration (FDA) publishes the amount of nicotine foun
QveST [7]

Answer:

We conclude that  the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 31.7 milligrams

Sample mean, \bar{x} = 28.5 milligrams

Sample size, n = 9

Alpha, α = 0.05

Sample standard deviation, s =  2.8 milligrams

First, we design the null and the alternate hypothesis

H_{0}: \mu = 31.7\text{ milligrams}\\H_A: \mu < 31.7\text{ milligrams}

We use One-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{28.5 - 31.7}{\frac{2.8}{\sqrt{9}} } = -3.429

Now, t_{critical} \text{ at 0.05 level of significance, 8 degree of freedom } = -1.860

Since,                  

t_{stat} < t_{critical}

We fail to accept the null hypothesis and accept the alternate hypothesis. We conclude that  the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.

3 0
3 years ago
X+16=24hvvcgcfcycdfdxfxxdgfv​
zaharov [31]

To do solve this you must isolate x. First subtract 16 to both sides (what you do on one side you must do to the other). Since 16 is being added to x, subtraction (the opposite of addition) will cancel it out (make it zero) from the left side and bring it over to the right side.

x + (16 - 16) = 24 - 16

x = 8

Check:

8 + 16 = 24

24 = 24

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0
3 years ago
Read 2 more answers
The annual tuition at a specific college was $20,500 in 2000, and $45,4120
nika2105 [10]

Answer: the tuition in 2020 is $502300

Step-by-step explanation:

The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = $20500

The fee in 2018 is the 19th term of the sequence. Therefore,

T19 = $45,4120

n = 19

Therefore,

454120 = 20500 + (19 - 1) d

454120 - 20500 = 19d

18d = 433620

d = 24090

Therefore, an

equation that can be used to find the tuition y for x years after 2000 is

y = 20500 + 24090(x - 1)

Therefore, at 2020,

n = 21

y = 20500 + 24090(21 - 1)

y = 20500 + 481800

y = $502300

6 0
3 years ago
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