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solong [7]
3 years ago
11

mouse scurries across your kitchen floor at 2.0 feet per second. How many miles can the mouse travel in 1.5 hours (rounded to th

e nearest tenth)?
Mathematics
2 answers:
ad-work [718]3 years ago
6 0
2.0 times 60= 120 feet per minute
120 times 90= 10,800.0 feet
10,800 times 0.000189= about 2.0 miles
Lera25 [3.4K]3 years ago
3 0

Answer: the mouse can travel a distance of 2.05 miles in 1.5 hours

Step-by-step explanation:

The speed of the mouse is 2ft/s

We want to know how many miles will the mouse travel in 1.5 hours, so the first steep is change the units:

1 mile = 5280 feet

so 2 feet =  (2/5280) miles

Then the speed is:

s = (2/5280) milles per second.

now, in one hour and half, we have 90 minutes, and a minute has 60 seconds, so 1.5 houes is equivalent to:

90*60s = 5400s

So the distance that the mouse moves in 1.5 hours in miles is:

D = (2/5280)*5400  miles = 2.05 miles

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kolezko [41]

So we know that the word 'product' means multiplication, and that means that h and 4 are being multiplied. Also, one-fifth of x is another way of saying that one-fifth is being multiplied with x. So then we can construct the equation:

\frac{1}{5} x-(4*h)=35

And we can then simplify this by taking out the multiplication sign:

\frac{1}{5}x-4h=35

And so since we do not know what x or h is equal to, this is as far as we can go.

8 0
3 years ago
WILL MARK BRAINLIEST!!!
patriot [66]

Answer:

option D.

Step-by-step explanation:

average rate of change in steel production over the eight days=-0.15 tons per day

Step-by-step explanation:

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6 0
3 years ago
Please help with these 3 questions
Sever21 [200]

Answer: x = 11

Step-by-step explanation:

2x+5 = 3x-6

2x-3x = -6-5

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x = 11

Double-check:
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4 0
2 years ago
Find the area of the shaded regions. GIve your answer as a completely simplified exact value in terms of pi. (No approximations)
Anon25 [30]

Answer:

A = 27π cm²

Step-by-step explanation:

Area of the shaded region = area of full circle of O - Area of the unshaded sector

= (πr²) - (θ/360*πr²)

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r = 6 cm

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Area of shaded region = (π*6²) - (90/360*π*6²)

= (36π) - (¼*π*36)

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Likurg_2 [28]
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