Complete Question
If a logo has dimensions of 6 ft and 11ft, he needs a quart of paint for every 22 square ft. How many quarts will he need for the whole logo?
Answer:
3 quarts of paint
Step-by-step explanation:
The Logo is rectangular in shape, hence:
The area of a rectangle = Length × Width
The logo has dimensions of 6 ft and 11ft.
Area of the Logo = 6ft × 11ft = 66ft²
He needs a quart of paint for every 22 square ft
Hence:
22 ft² = 1 quart of paint
66ft² = x
Cross Multiply
22 ft² × x = 66 ft² × 1 quart
x = 66 ft² × 1 quart/22 ft²
x = 3 quarts of paint
Therefore, he will need 3 quarts of paint for the whole logo.
Answer:
1.1x10^24
Step-by-step explanation:
Step-by-step explanation:
ABC is an isoceles triangle (both legs are equally long). and AB is its baseline.
OC is now a median for ABC splitting the angle at C and AB in half.
so, we have 2 right-angled triangles : OAC and OBC.
the half-angles at C are 42/2 = 21°.
the angles at A and B are 90°.
and the half-angles at O are 180 - 90 - 21 = 69°.
remember that the sum of all angles in a triangle must always be 180°.
AB are the heights of both of these triangles.
the single height is sin(69)×7 = 6.535062985... cm
and so,
AB = 2× height = 13.07012597... cm.
The answer is c alternate exterior angles
Forty-thousand, five-hundred eighty-three.
