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MakcuM [25]
3 years ago
15

World pade is world processing software true or false​

Computers and Technology
1 answer:
Evgesh-ka [11]3 years ago
5 0

Answer:

yes

Explanation:

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This program will convert a set of temperatures from Fahrenheit to Celsius and Kelvin. Your program will be reading in three dou
Naily [24]

Answer:

see explaination

Explanation:

#include<iostream>

#include<iomanip>

using namespace std;

int main()

{

double temp1,temp2,inc,cel;

int i=1;

while(i==1)

{

i=0;

cin>>temp1>>temp2>>inc;

if(temp2<temp1||inc<=0)

{

i=1;

cout<<"Starting temperature must be <= ending temperature and increment must be >0.0\n";

}

}

cout<<endl;

cout<<setw(15)<<"Fahrenheit"<<setw(15)<<"Celsius";

while(temp1<=temp2)

{

cel=(temp1-32)/1.8;

cout<<endl;

cout<<fixed<<setprecision(3)<<setw(15)<<temp1<<setw(15)<<cel;

temp1+=inc;

}

}

Please kindly check attachment for output.

8 0
3 years ago
SUB2 WWolfPlays on yt <br><br><br> true or false if false ima cri
VMariaS [17]

Answer:

True

Explanation:

Plz brainlist

5 0
3 years ago
Read 2 more answers
A combination lock has the following basic properties:
fomenos

Answer:

public class CombinationLock {

   

    private int combinationNumber1 = 0;

    private int combinationNumber2 = 0;

    private int combinationNumber3 = 0;

   

   CombinationLock(int combinationNumber1, int combinationNumber2, int combinationNumber3){

       this.combinationNumber1 = combinationNumber1;

       this.combinationNumber2 = combinationNumber2;

       this.combinationNumber3 = combinationNumber3;

   }

   

   public boolean open(int number1, int number2, int number3){

       if(number1 == combinationNumber1 && number2 == combinationNumber2 && number3 == combinationNumber3)

           return true;

       else

           return false;

   }

   

   public boolean changeCombo(int number1, int number2, int number3, int newNumber1, int newNumber2, int newNumber3){

       

       if (open(number1, number2, number3)){

           combinationNumber1 = newNumber1;

           combinationNumber2 = newNumber2;

           combinationNumber3 = newNumber3;

           return true;

       }else

           return false;

   }

}

Explanation:

- <em>Three variables</em> are created to hold the combination.

- A <em>constructor</em> is created to set the combination.

- A boolean method called <em>open</em> is created to check if the given numbers are correct, and <u>returns true</u> (<u>otherwise returns false</u>).

- A boolean method method called <em>changeCombo</em> is created to check if given numbers are correct. If they are correct, it assigns new values for the combination and <u>returns true</u> (<u>otherwise returns false</u>).

5 0
3 years ago
Someone help me
valkas [14]

The program is an illustration of loops.

Loops are used to perform repetitive and iterative operations.

The program in C++ where comments are used to explain each line is as follows:

#include <iostream>

using namespace std;

int main(){

   //This declares and initializes all variables

   string star = "*", blank = " ", temp;

   //The following iteration is repeated 8 times

   for (int i = 1; i <= 8; i++) {

       //The following iteration is repeated 8 times

       for (int j = 1; j <= 8; j++) {

           //This prints stars

           if (j % 2 != 0) {

               cout << star;

           }

           //This prints blanks

           else if (j % 2 == 0) {

               cout << blank;

           }

       }

       //This swaps the stars and the blanks

       temp = star;

       star = blank;

       blank = temp;

       //This prints a new line

       cout << endl;

   }

}

Read more about similar programs at:

brainly.com/question/16240864

5 0
3 years ago
Let's consider a long, quiet country road with houses scattered very sparsely along it. (We can picture the road as a long line
Rus_ich [418]

Answer:

Follows are the solution to these question:

Explanation:

A simple gullible algorithm is present. Let h mark the house to the left. Then we put a base station about 4 kilometers to the right. Now delete and repeat all the houses protected by this base station. In this algorithm, they can simply be seen to position baselines at b1, . . , bk as well as other algorithms (which may be an optimum algorithm) at b'_{1}, \ . . . . . . ,b'_{k'}  and so on. (from left to right)   b_1 \geq b'_{1},\ \  b_2 \geq b'_{2} That's why k \leq k'.

7 0
3 years ago
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