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3 years ago

What is inter quartile range?

1 answer:

5 0

The difference between the number marking the third quartile (Q3) and the number marking first quartile (Q1).

Do you have a set of numbers you need help with?

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You have five quarts of paint. It takes 5/8 quart to paint each chair you are asked to paint. How many chairs can you paint?

pentagon [3]

5 chairs it is because it's oberse

3 0

3 years ago

Prove the polynomial identity.

Ronch [10]

Answer:

The answer to your question is: 2, 4, 5, 1 , 3

Step-by-step explanation:

The first line is the second

(3x² - 6)² - (3x²)² = 36(1 - x)(1 + 1)

The second line is the forth

9x⁴ - 36x² + 36x² - 9x⁴ = 36(1 - x)(1 + x)

The next line is the fifth

36 - 36x² = 36(1 - x)(1 + x)

The next line is the first

36(1 - x²) = 36(1 - x)(1 + x)

The last line is the third

36(1 - x)(1 + x) = 36(1 - x)(1 + x)

3 0

3 years ago

Read 2 more answers

This year, the Newville Tigers won six games more than the Wilton Panthers won. The Tigers won 22 games. Which equation cannot b

Usimov [2.4K]

Answer:

The ones that can be used are (B and A)

The ones that cannot be used are (C and D)

Step-by-step explanation:

Because the panthers got 6 less and the tigers got 22…

b+6 would make 22 (panthers plus 6 makes tigers)

22-b would also be 6 because 6+b makes 22, so subtracting b from 22 makes 6

5 0

3 years ago

Quickly what is the answer to this and why

Darya [45]

Answer:

Q = 146

Step-by-step explanation:

We know that angle S and T are equal because the sides are equal

The measure of the exterior angle is equal to the sum of the opposite interior angles in a triangle

Q = S+T

Q = S+S

Q = 2S

Q =2* 73

Q = 146

5 0

3 years ago

What is the antiderivative of 3x/((x-1)^2)

Maslowich

Answer:

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Step-by-step explanation:

Given

$\int \:\:3\cdot \frac{x}{\left(x-1\right)^2}dx$

$\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx$

$=3\cdot \int \frac{x}{\left(x-1\right)^2}dx$

$\mathrm{Apply\:u-substitution:}\:u=x-1$

$=3\cdot \int \frac{u+1}{u^2}du$

$\mathrm{Expand}\:\frac{u+1}{u^2}:\quad \frac{1}{u}+\frac{1}{u^2}$

$=3\cdot \int \frac{1}{u}+\frac{1}{u^2}du$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx$

$=3\left(\int \frac{1}{u}du+\int \frac{1}{u^2}du\right)$

$\int \frac{1}{u}du=\ln \left|u\right|$ ∵ $\mathrm{Use\:the\:common\:integral}:\quad \int \frac{1}{u}du=\ln \left(\left|u\right|\right)$

$\int \frac{1}{u^2}du=-\frac{1}{u}$ ∵ $\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1$

$=3\left(\ln \left|u\right|-\frac{1}{u}\right)$

$\mathrm{Substitute\:back}\:u=x-1$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)$

$\mathrm{Add\:a\:constant\:to\:the\:solution}$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Therefore,

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

4 0

3 years ago