suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
Answer:
LaTasha is correct. There is no correlation between x and y. The slope of the line of best fit is zero, which shows that there is no negative or positive correlation.
Answer: 85 pages
cross multiply 60 x 17 = 1020 / 12 = 85
17 85
— = —
12 60
5 2/3 divided by 2 2/3 = 17/3 divided by 8/3 = 17/8 = 2 1/8 miles per hour
2 2/3 divided by 5 2/3 = 8/3 divided by 17/3 = 8/17 hours per mile