Substitution doesn't work for this, but elimination does.
-6x-8y=-20 +6( x+6y=-6)
-6x-8y=-20 + 6x+36y=-36
-6x and 6x cancel each other, add -8 and 36 to get 28, and -20 and -36 to get -56.
28y=-56
divide by 28 on both sides.
Y= -2
Then substitute y into one of the equations.
x+6(-2)=-6
x-12=-6
x=6
The ordered pair is (6,-2).
Answer:
First one is 41
Second one is 87
Step-by-step explanation:
Make the shaded part as a trapezoid which is (3+6)*10/2 you just have to get rid of 2*2. So you get 41 as the answer.
The unshaded part will be 16*8 then subtracts the shaded part which is 41. Then you get the answer 87.
Answer:
Step-by-step explanation:
LOL The graph doesn’t match the y intercept :)
Anyway
If we have point (0,-3) we have a quadratic of
y=ax^2+bx-3 we are given points (-1,0) and (2,0) so
a-b-3=0 and 4a+2b-3=0
4a+2b-3+2(a-b-3)=0
4a+2b-3+2a-2b-6=0
6a-9=0
6a=9
a=1.5, since a-b=3
1.5-b=3
b=-1.5
y=1.5x^2-1.5x-3
1. the combinations are 5 and 3 twice and 3 and 4 twice
5+3+5+3+3+4+3+4= 30 L
2. Trya can ride 12 , 18, 24,30 kilometres are the possible distance
3. lexi can put 4 ribbons and 2 photos on her bulletin that is 40 cm meters.
ribbons 4×4=16
bulletin 12×2=24
altogether 40 cm with nothing overlapping
4. don't know dollars and centd sorry I know pounds as I am British
