Answer:
a.) 3x = 18 (where x = width)
b.) Area = 66 squared feet
Step-by-step explanation:
2{x + (2x-1)} = 34
3x - 1 = 17
x = 6 feet
length = 11 feet
Area = x (2x -1)
Answer:
it is 23. always remember it's supposed to add up to 180. So add up all your numbers and subtract the total from 180 to get your answer
Answer:x = - 5
y = 2
Step-by-step explanation:
The given system of simultaneous equations is expressed as
x + 3y = 1 - - - - - - - - - - - - - -1
4x + 4y = -12 - - - - - - - - - - - 2
We want to eliminate x. Multiplying equation 1 by 4 and equation 2 by 1, it becomes
4x + 12y = 4
4x + 4y = - 12
Subtracting the second equation from the first equation, it becomes
8y = 16
y = 16/8 = 2
Substituting y = 2 into equation 1, it becomes
x + 3 × 2 = 1
x + 6 = 1
x = 1 - 6 = - 5
Answer:
The upper 20% of the weighs are weights of at least X, which is 
, in which 
is the standard deviation of all weights and 
is the mean.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Upper 20% of weights:
The upper 20% of the weighs are weighs of at least X, which is found when Z has a p-value of 0.8. So X when Z = 0.84. Then
The upper 20% of the weighs are weights of at least X, which is , in which is the standard deviation of all weights and is the mean.
The probability that a student scored less than 55% on the exam is 0.134%.
<h3>What is a normal distribution?</h3>
It's the probability curve of a continuous distribution that's most likely symmetric around the mean. On the Z curve, at Z=0, the chance is 50-50. A bell-shaped curve is another name for it.
We have:
Mean of the sample = 70
Standard deviation = 5
= P(X<55%)
Z = (55-70)/5
Z = -3
P(X < -3)
From the Z table:
P(x<-3) = 0.0013499
or
P(x<-3) = 0.134%
Thus, the probability that a student scored less than 55% on the exam is 0.134%.
Learn more about the normal distribution here:
brainly.com/question/12421652
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