To solve for x, you need to isolate/get the variable "x" by itself in the equation:
3x - 3(x + 1) = 3 Distribute/multiply -3 into (x + 1)
3x + (-3)x + (-3)1 = 3
3x - 3x + 1 = 3
1 = 3
Your answer is no solution because the variable "x" is canceled out and 1 ≠ 3
A) I would make the positive integer x and then form an equation.
x + 30 = x^2 - 12
x + 42 = x^2
0 = x^2 - x - 42 this can be factorised
(x - 7) ( x + 6) Therefore x = 7 or x = -6
Since the question asks for a positive integer the answer is 7.
B) two positive numbers x and y.
X - y = 3
x^2 + y^2 = 117
Use these simultaneous equations to figure out each number.
Rearrange the first equation
x = y + 3
Then substitute it into the second equation.
(y+3)^2 + y^2 = 117
y^2 + 6y + 9 + y^2 = 117
2y^2 + 6y - 108 = 0
then factorise this.
(2y - 12) (y + 9)
This means that y = 6 or y = -9 but it’s 6 because that’s the only positive number.
Use y to find x
x = y + 3
x = 6 + 3
x = 9
So the answers are x = 9 and y = 6.
Answer:
Vamos a inventa tres multiplicaciones de seis factores en la que el resultado sea positivo, es decir un número mayor que cero, en la otra negativo, es decir, un número menor que cero y por último otra multiplicación que de como resultado el cero "0".
Primero recordemos que:
Los factores son los números que se multiplican.
Seis factores serían 6 números.
Multiplicación con resultado positivo, es decir mayor a 0:
2×3×4×2×1×5=240
Multiplicación con resultado negativo, es decir menor a 0:
-4×2×5×2×1×10= -400
Multiplicación con resultado cero:
2×4×6×7×11×0=0
Step-by-step explanation:
Brainliest please
Answer:
Yes
Step-by-step explanation:
After solving for the two values of a, the second inequality gives a value inside the range of the first inequality.
Answer: see below
<u>Step-by-step explanation:</u>
(1)
b) FH = 6, EG = 6
c) Square (which means it is also a rectangle and parallelogram)
(2)
c) Parallelogram
