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2 years ago

13

Please answer need help

2 answers:

Temka [501]2 years ago

6 0

C :)

Have a good day!!

12345 [234]2 years ago

4 0

Answer: The third one is the correct answer

Step-by-step explanation: I hope this helps

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What are the coordinates of the focus of the parabola shown below?

soldi70 [24.7K]

The coordinates are (-4,0),(0,-1)

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3 years ago

The triangles below are similar. Triangle A B C. Side A C is 10 and side A B is 5. Angle C is 30 degrees. Triangle D E F. Side E

Gnoma [55]

Answer:

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$\triangle CBA {\displaystyle \sim } \triangle FED$

$\triangle BAC {\displaystyle \sim } \triangle EDF$

Step-by-step explanation:

Given

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$AC = 10$

$AB = 5$

$\angle C = 30^\circ$

$ED = 7.5$

$DF = 25$

$\angle F =30$

$\angle E =90$

Required

Which of the options is/are true:

$\triangle CBA {\displaystyle \sim } \triangle FED$ $\triangle CBA {\displaystyle \sim } \triangle FDE$ $\triangle BAC {\displaystyle \sim } \triangle EFD$

$\triangle BAC {\displaystyle \sim } \triangle EDF$ $\triangle ABC {\displaystyle \sim } \triangle DE\ F$ $\triangle ABC {\displaystyle \sim } \triangle DFE$

The given triangles, implies that:

$A {\displaystyle \sim } \ D$

$B {\displaystyle \sim } \ E$

$C {\displaystyle \sim } \ F$

By taking each sides of both triangle, one after the other; the possible similar triangles are:

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$\triangle CBA {\displaystyle \sim } \triangle FED$

$\triangle BAC {\displaystyle \sim } \triangle EDF$

5 0

3 years ago

(picture)⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Brums [2.3K]

Answer:

196

Step-by-step explanation:

70% multiply by 4/5(80%) which is 56%

56% times 350

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2 years ago

Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE

Furkat [3]

Answer:

x = -6 and x = 4

Step-by-step explanation:

In math, the critical points of a function are the points where the derivative equals zero.

So, first we will find the derivative of the function. The derivative is:

$f'(x)=3x^2 +6x-72$

Now, we are going to make the derivative equal zero and find the answers of the equation.

$3x^2 +6x-72=0\\3(x^2 +2x-24)=0\\3(x+6)(x-4)=0\\$

So we have that the critical points are the answers to this equation:

$x+6= 0 \\x= - 6$

and

$x-4=0\\x=4$

Thus, the critical points are x=-6 and x=4

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3 years ago

Solve the following formula for m<br><br> C = amt<br><br> m =<br><br> Answer as expression

d1i1m1o1n [39]

M=c/at

Divide both sides by a and t to isolate m. Then the solution is just m=c/at

4 0

3 years ago