The value of the product expression (-2x-9y²)(-4x-3) is 8x² + 6x + 27y² + 36xy²
<h3>How to evaluate the product?</h3>
The expression is given as:
(-2x-9y²)(-4x-3)
Expand the expression
8x² + 6x + 27y² + 36xy²
Hence, the value of the product expression (-2x-9y²)(-4x-3) is 8x² + 6x + 27y² + 36xy²
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We are asked to determine the limits of the function cos(2x) / x as x approaches to zero. In this case, we first substitute zero to x resulting to 1/0. A number, any number divided by zero is always equal to infinity, Hence there are no limits to this function.
Usual limit of sin is sinX/X--->1, when X--->0
sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x= [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
=(sin3x / 3x) . (3/5x^2- 4)
finally lim sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
x----->0 x---->0
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Step-by-step explanation:
