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LekaFEV [45]
3 years ago
5

Simplify 3 × 3x² × y × 4z × x × y × z

Mathematics
2 answers:
geniusboy [140]3 years ago
6 0

Answer : 36x³z²y²

<h3>Firstly, you have to know these:</h3>

<em>a³ × a² = </em>a^{3+2} = a^{5}<em />

<em>a³ × b³ = (ab)³</em>

<em>a × b = ab</em>

<em>a × b × c = abc</em>

<em>a³ × a² × b = </em>a^{5}b<em />

<h3>Simplfy 3 × 3x² × y × 4z × x × y × z</h3>

rewrite like this => 3 × 3x² × x × 4z × z × y × y => you can understand better. I didn't change any number. I only change number's places

3 × 3x² × x × 4z × z × y × y <em>===></em> 9x³ × 4z × z × y × y

3 × 3x² × x × 4z × z × y × y <em>===> </em>3 × 3x² × x × 4z² × y × y

3 × 3x² × x × 4z × z × y × y <em>===> </em>3 × 3x² × x × 4z × z × y²

So;

3 × 3x² × x × 4z × z × y × y = 9x³ × 4z² × y²

9x³ × 4z² × y² = 36x³z²y²

<u><em></em></u>

Hope this helps ^-^

lesantik [10]3 years ago
5 0

this should be correct if not then idk

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4x + y = 3 -2x + 3y = -19 what's the solution plz help
Rainbow [258]

The solution to given system of equations is x = 2 and y = -5

<em><u>Solution:</u></em>

<em><u>Given the system of equations are:</u></em>

4x + y = 3 ---------- eqn 1

-2x + 3y = -19 ---------- eqn 2

We have to find the solution to above system of equations

<em><u>We can solve the system by substitution method</u></em>

From eqn 1,

4x + y = 3

Isolate y to one side

y = 3 - 4x ----------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

-2x + 3(3 - 4x) = -19

-2x + 9 - 12x = -19

Combine the like terms

-14x = -19 - 9

-14x = -28

Divide both sides of equation by -14

<h3>x = 2</h3>

<em><u>Substitute x = 2 in eqn 3</u></em>

y = 3 - 4(2)

y = 3 - 8

<h3>y = -5</h3>

Thus the solution is x = 2 and y = -5

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