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TiliK225 [7]
4 years ago
7

Mark lives 5,000 feet from school. He walks to school at a steady rate of 250 feet per minute. Use that information and the diag

ram to complete the statements below
Mathematics
2 answers:
vladimir1956 [14]4 years ago
7 0

Answer:

4.329 miles per hour... im pretty sure

Step-by-step explanation:

i hope this helps.....

Alexeev081 [22]4 years ago
3 0

Answer:

I need the diagram but here is all the info you can have with this.

Step-by-step explanation:

It takes 20 minutes to walk from home to school.

He walks just over 4 steps a second.

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What percent of 2000 is 160?<br> Show work
ArbitrLikvidat [17]

Hello from MrBillDoesMath!

Answer:

.08%

Discussion:

Let the percent be denoted "p". Then

2000 * p% = 160 =>     ( as p% = p/100)

2000* p/100 = 160 =>

20p = 160 =>

p = 8 or .08%



Regards,  

MrB


5 0
3 years ago
Read 2 more answers
If integer k is equal to the sum of all even multiples of 15 between 295 and 615, what is the greatest prime factor of k?
ohaa [14]

Answer:

The greatest prime factor of k is 11.

Step-by-step explanation:

∵  LCM( 2, 15) = 30,

Thus, the even multiple of 15 must be multiple of 30,

That is, the even multiple of 15 between 295 and 615 are

300, 330, 360,..........600

Which is an AP,

Having first term, a = 300,

Common difference, d = 30,

If n be the number terms,

Last term = a+(n-1)d

=300+(n-1)30

=270 + 30n

\implies 270+30n = 600\implies 30n = 330\implies n = 11

Hence, the sum of the all even multiple of 15 from 295 to 615,

S_{11}=\frac{11}{2}(2(300)+(11-1)30)=\frac{11}{2}(600+300)=\frac{11}{2}(900)=11\times 450

According to the question,

S_{11}=k

⇒ k = 11 × 450 = 11 × 5 × 5 × 3 × 3 × 2

Hence, the greatest prime factor of k is 11.

3 0
3 years ago
On the west coast of Canada, crows eat whelks (a shellfish). To open the whelks, the crows drop them from the air onto a rock. I
RideAnS [48]

Answer:

a) d= 2x + (54/x)

b) x = √27 m ≈ 5.2 m

Step-by-step explanation:

a) Given

The average number of drops = n  

Height in meters from the point where the whelk is dropped = x

If   n(x) = 1 + (27/x²)

Then, the total vertical distance the crow travels upward to open a whelk is the height (x) times the average number of times the crow has to fly upwards to try again

d = 2xn = 2x*(1 + (27/x²)) = 2x + (54/x)

b) To minimize the distance consider the first derivative

d' = (2x + (54/x))' = 2 - (54/x²)

and d' = 0  give us (x must be positive)

2 - (54/x²) = 0  ⇒  x = √27 m ≈ 5.2 m

5 0
3 years ago
Solve 2x 2 + 8x - 12 = 0 by completing the square. What are the solutions?
oee [108]
I attached a picture of how I worked out the answer

5 0
4 years ago
The amount that two groups of students spent on snacks in one day is shown in the dot plots below. Which statements about the me
RUDIKE [14]

Answer:

  • The mean for Group A is less than the mean for Group B.
  • The median for Group A is less than the median for Group B.
  • The mode for Group A is less than the mode for Group B.

Step-by-step explanation:

First, we can find the measures of center for each group.

<u>Group A</u>

Mode: 1

Median: (1 + 2) / 2 = 3 / 2 = 1.5

Mean: (1 * 5 + 2 * 4 + 3) / 10 = (5 + 8 + 3) / 10 = 16 / 10 = 1.6

<u>Group B</u>

Mode: 3

Median: 92 + 3) / 2 = 5 / 2 = 2.5

Mean: (1 * 3 + 2 * 2 + 3 * 4 + 5) / 10 = (3 + 4 + 12 + 5) / 10 = 24 / 10 = 2.4

From here, we can see that...

  • The mean for Group A is less than the mean for Group B.
  • The median for Group A is less than the median for Group B.
  • The mode for Group A is less than the mode for Group B.

Hope this helps!

8 0
4 years ago
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