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babymother [125]
3 years ago
13

For 2x+3y=12 find y when x=0

Mathematics
1 answer:
EastWind [94]3 years ago
7 0

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2(0) + 3y = 12

3y = 12

Divide sides by 3

\frac{3y}{3}  =  \frac{12}{3}   \\

y = 4

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Find the HCF and LCM of 160 and 252 by prime factorisation method and verify that HCF x LCM = Product of the two given numbers.
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Answer:

HCF=4

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HCF x LCM = Product of the two given numbers is verified because 403200=40320

Step-by-step explanation:

HCF of 160 and 252

HCF is the product of common prime factors

Prime Factorisation of 160: 2x2x2x2x2x5

Prime Factorisation of 252: 2x23x3x7

HCF= 2x2

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40 and 63 doesn't come in any other table together so,

HCF= 2 x 2 = 4

Now, finding LCM of 160 and 252

LCM is the product of all factors of both numbers, while if any factor is common, it is considered once.

Prime Factorisation of 160: 2x2x2x2x2x5

Prime Factorisation of 252: 2x23x3x7

In the given factors 2x2 is common so, it is considered once.

LCM= 2x2x2x2x2x3x5x7

LCM= 10080

Now, checking:

HCF x LCM = Product of the two given numbers.

4x10080=160x252

403200=40320

So, It is verified that HCF x LCM = Product of the two given numbers.

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