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Diano4ka-milaya [45]
4 years ago
9

A comparison number sentence

Mathematics
1 answer:
andreev551 [17]4 years ago
3 0
I need a little more to work with
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Triangle MAT is isosceles, angle A is the vertex angle, AT = 8x-3, MT = 2x+3 and MA=5x+15. Find the value of x and the indicated
Anvisha [2.4K]

Answer:

x=6, AT=45, MT=15,  MA=45

Step-by-step explanation:

Because it is isosceles, MA=AT, so 8x-3=5x+15, solve for x and then plug it into the equations.

3 0
3 years ago
At the end of April, Mandy told Bill that she has read 16 books this year and reads 2 books each month. Bill wants to catch up t
Dovator [93]

we know that

In an Arithmetic Sequence the difference between one term and the next is a constant

an=a1+d*(n-1)

where

a1 is the first term

d is the common difference between terms

n is the number of months (in this problem)

case a) Mandy

a1=16 books

d=2

an=16+2*(n-1) ------> equation 1

in this equation the first month is April

case b) Bill

a1=4 books

d=4

an=4+4*(n-1) -------> equation 2

In this equation the first month is May

With the equation 1 and the equation 2

calculate the attached table

therefore

the answer is

December

8 0
3 years ago
Read 2 more answers
A rectangular yard measuring 26 ft by 36 ft is bordered (and surrounded) by a fence. Inside, a walk that is 2 ft wide goes all t
cestrela7 [59]

Answer:

  232 square feet

Step-by-step explanation:

The outside dimensions of the yard are 26 ft by 36 ft, so its total area is ...

  yard including walk = (26 ft)(36 ft) = 936 ft²

The dimensions of the yard inside the walkway are 22 ft by 32 ft, so that area is ...

  yard not including walk = (22 ft)(32 ft) = 704 ft²

The difference in these areas is the area of the walkway:

  walkway area = (yard including walk) - (yard not including walk)

  = (936 -704) ft² = 232 ft² . . . . area of the walk

_____

Another way to figure this is to consider the length of the centerline of the walkway. That is the perimeter of a rectangle that is 24 ft by 34 ft. The perimeter (centerline length) is 116 ft, and the width of the walk is 2 ft, so its area is ...

  (116 ft)(2 ft) = 232 ft²

4 0
3 years ago
I need help can someone help me (:
vladimir2022 [97]
Hey there!

To solve the first problem, I've found it easiest to solve the equation for, say, values –2 through +2 and create a table of values for you to begin graphing this function. You may need to do more depending on the equation itself. 

Some points are: (–2, 0.75), (–1, 1.5), (0, 3), (1, 6) and (2, 12). You can check which graph matches up with these points the closest to get your answer of D. 

To solve the second problem, you'll need to use the distance equation.

x1 = –4, y1 = 3
x2 = –1, y2 = 1 
  ___________________
√ (x2–x1)^2 + (y2–y1)^2
  _________________
√ (–1–(–4)^2 + (1–3)^2
  _______________
√ (–1+4)^2 + (–2)^2
  ____________
√ (3)^2 + (–2)^2
  _____
√ 9 + 4
  ___
√ 13, making your answer D

For your third question, I always just counted the number of units the point was from the line of reflection. You'll count twice diagonally towards the line from point C for this one, staying on the "crosshairs" of the graph. All you need to do then is count two diagonal units along the same line, then you'll get your answer of (2, 6), or D. 

For your final question, A and B are immediately out, since they won't be parallel to the 4x equation. You'll need to solve both of your remaining equations for y with 2 plugged in for x; whichever one equals 7 will be your answer. In this case, it will be D. 

Hope this helped you out! :-)
3 0
3 years ago
Let x= -1, y= -2 and z = 3 evaluate the following expression x/5y - 2z
RideAnS [48]
Just substitute the values: -1/-10-6 -> -1/-16 -> 1/16.
8 0
3 years ago
Read 2 more answers
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