Answer:
Step-by-step explanation:
Let the equation of the perpendicular line is,
y = mx + b
where m = slope of the line
b = y-intercept
From the graph, slope of the line passing through (0, -1) and (3, 1),
m' =
m' =
m' =
To get the slope (m) of this line we will use the property of perpendicular lines,
m × m' = (-1)
m × = -1
m =
Equation of the perpendicular line will be,
x-intercept of the line is (-3) therefore, point on the line is (-3, 0)
0 =
b =
Equation of the line will be,
Answer:
Step-by-step explanation:
We are asked to find the equation of a line given a point and the slope. We will use the point-slope formula.
In this formula, m is the slope and (x₁, y₁) is the point the line passes through. The slope of this line is -4 and the line passes through (-2,5).
Substitute the values into the formula.
We are finding the equation of the line, so we should find the slope-intercept form or y=mx+b ( where m is the slope and b is the y-intercept).We must isolate the variable y on one side of the equation.
First, distribute the -4 on the right side of the equation. Multiply each term inside the parentheses by -4.
5 is being subtracted from y. The inverse operation of subtraction is addition, so we will add 5 to both sides of the equation.
The equation of the line is y= -4x -3. The slope of the line is -4 and the y-intercept is -3.