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3 years ago

BRAINLIEST ASAP! PLEASE HELP ME :)

Mathematics

1 answer:

marta [7]3 years ago

6 0

<h3>Answer: C) none of the equations are identities</h3>

If you plugged theta = 0 into the first equation, then you would have

sin(45) + cos(45) = sin(0) + cos(0)

sqrt(2) = 1

which is a false equation. We don't have an identity here.

The same story happens with the second equation. Plug in theta = 0 and it becomes

cos(60) - sin(60) = cos^2(0) + tan(0)

1/2 - sqrt(3)/2 = 1 + 0

-0.37 = 1

which is false.

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mr_godi [17]

The answer is a = $\frac{4}{-3}$

Step-by-step explanation:

1. Convert the mixed fraction to an improper fraction

To find the numerator, multiply the denominator by the whole number and add the numerator to it.

The denominator remains the same.

So, 2 $\frac{2}{3}$ will be $\frac{8}{3}$

2. Now the equation is,

$\frac{3}{2}$ a - $\frac{4}{3}$ a = $\frac{10}{3}$ + $\frac{8}{3}$ a

3. Take LCM on both sides.

For the left side, multiply the first fraction by $\frac{3}{3}$ and multiply the second fraction by $\frac{2}{2}$

$\frac{3*3}{2*3}$ a - $\frac{4*3}{3*3}$ a = $\frac{10+8a}{3}$

4. Solve by making a the subject

$\frac{9a-8a}{6}$ = $\frac{10+8a}{3}$

$\frac{a}{6}$ = $\frac{10+8a}{3}$

$\frac{3a}{6}$ =10+8a

$\frac{a}{2}$ = 10 + 8a

a = 2(10 + 8a)

a = 20 + 16a

a-16a = 20

-15a = 20

a = $\frac{20}{-15}$

a = $\frac{4}{-3}$

Therefore, the answer is a = $\frac{4}{-3}$

Keyword: Equations

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3 years ago