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madreJ [45]
3 years ago
14

If a salesperson sells a car at a profit of $1,000, how much will the commission be? If the car is sold for a $1,500 profit, wha

t will the commission be?
Mathematics
1 answer:
Ahat [919]3 years ago
6 0

Answer:

The graph (or piecewise function) shows that for a profit of $1,000 the salesperson will earn a commission of 17%:

      C(p) = 0.17 p

C(1,000) = 0.17 (1,000)

C(1,000) = 170

Therefore, the salesperson will earn $170 as commission on a profit of $1,000.

If the car sells for a profit of $1,500, the commission will still be 17%. This commission is governed by the second equation because the third equation (21%) does not include the endpoint 1,500. So:

      C(p) = 0.17 p

C(1,500) = 0.17 (1,500)

C(1,500) = 255

The salesperson will earn $255 as commission on a profit of $1,500.

Step-by-step explanation:

answer for plato

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For each set of probabilities, determine whether the events A and B are independent or dependent.
lozanna [386]

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  • (a) Independent
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  • (c) Dependent
  • (d) Independent

========================================================

Explanation:

If events A and B are independent, then the two following equations must both be true

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This is because the conditional probability P(A|B) means "P(A) when B has happened". If B were to happen, then P(A) must be the same as before. In other words, event B does not affect A, and vice versa.

For part (a), we have P(B) = 1/4 and P(B|A) = 1/4 showing that P(B|A) = P(B) is true, and therefore we can say the events are independent. We don't need the info that P(A) = 1/8.

------------------------

Unlike part (a), part (b) has the answer "dependent" because P(A) = 1/8 and P(A | B) = 1/3 differ in value. Event A starts off at probability 1/8, but then event B occurring means P(A) gets increased to 1/3. The prior knowledge about B changes the chances of A. The P(B) = 1/5 is unneeded.

------------------------

If A and B were independent, then,

P(A and B) = P(A)*P(B)

However,

P(A)*P(B) = (1/4)*(1/5) = 1/20

which is not the same as P(A and B) = 1/6. Therefore the two events are dependent.

------------------------

Refer back to part (a)

P(A) = 1/4 and P(A|B) = 1/4 are identical in value, so P(A|B) = P(A) which leads to the events being independent. Whether we know event B happened or not, it does not affect the outcome of event A. P(B) = 1/9 is unneeded.

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