The first digit of the quotient is the first number of the answer of your division problem. the answer is 2
+ y = -1 ⇒ y =
- 1
To graph this line, plot a point at the y-intercept (0, -1), than plot the next point using the rise over run from the slope
by counting up 1 and to the right 3 of the y-intercept. This gives you a second point of (3. 0). Draw a line through those two coordinates.
Answer: Plot (0, -1) and (3, 0) and draw a line through them.
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y = 4 +
⇒ y =
+ 4
Same as above. Plot the y-intercept (0, 4) and then use rise over run from the slope to plot (3, 5).
Answer: Plot (0, 4) and (3, 5) and draw a line through them.
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You should end up with two PARALLEL lines. Since the lines never intersect, there are no solutions to this system of equations.
Answer: No Solution
Answer:
10a: △ABC is an Equilateral triangle with all acute angles.
10b: △BCD is A scalene triangle with all acute angles.
10c: △BDE is An Isosceles triangle with one obtuse angle.
Step-by-step explanation:
10) Looking at the diagram at the bottom left;
- △ABC has 3 equal internal angles and as such, it means it will have 3 equal angles.
Thus, we can classify it as; Equilateral triangle with all acute angles.
- △BCD has 3 unequal angles. Thus, it's 3 sides are not equal. Also all the angles are less than 90°.
We can classify it as;
A scalene triangle with all acute angles
- △BDE has 2 equal angles and one angle greater than 90°. This means it has 2 equal sides.
Thus, we can classify it as;
- An Isosceles triangle with one obtuse angle.
Answer:
D) There will be close to 3030 football players but probably not exactly 3030 football players who get a popsicle.
Step-by-step explanation:
We know that the Hendricksons are in charge of bringing treats for 5050 football players.
They brought 33 coolers of popsicles and 22 coolers of ice cream sandwiches. Each player is going to randomly select a cooler from which to get their treat.
We conclude that:
D) There will be close to 3030 football players but probably not exactly 3030 football players who get a popsicle.