Answer: If Mo eats 1 1/2 pounds of hay, Larry and Curly together eat less.
Larry and Curly eat 17/12 or 1 5/12 pounds of hay together.
Mo eats more hay than Larry and Curly combined.
Step-by-step explanation: Add the fractions by finding the Least Common Denominator 3/4 = 9/12. 4/6 = 8/12.
9/12 +8/12 =17/12.
1 1/2 = 18/12
Answer:
![\boxed{ \frac{ \sqrt[3]{ {x}^{11} } }{4} }](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B%20%7Bx%7D%5E%7B11%7D%20%7D%20%7D%7B4%7D%20%7D%20)
Step-by-step explanation:
![= > \frac{ {x}^{4} }{ \sqrt[3]{64x} } \\ \\ = > \frac{ {x}^{4} }{ {(64x)}^{ \frac{1}{3} } } \\ \\ = > \frac{ {x}^{4} }{ ({64}^{ \frac{1}{3} } )\times ({x}^{ \frac{1}{3} } )} \\ \\ = > \frac{ {x}^{4} }{ ({( {4}^{3} )}^{ \frac{1}{3} }) \times( {x}^{ \frac{1}{3} } )} \\ \\ = > \frac{ {x}^{4} }{ ({4}^{ \cancel{3} \times \frac{1}{ \cancel{3}} } ) \times( {x}^{ \frac{1}{3} } )} \\ \\ = > \frac{ {x}^{4} }{4 {x}^{ \frac{1}{3} } } \\ \\ = > \frac{ {x}^{4 - \frac{1}{3} } }{4} \\ \\ = > \frac{ {x}^{ \frac{12 - 1}{3} } }{4} \\ \\ = > \frac{ {x}^{ \frac{11}{3} } }{4} \\ \\ = > \frac{ \sqrt[3]{ {x}^{11} } }{4}](https://tex.z-dn.net/?f=%20%3D%20%20%3E%20%20%5Cfrac%7B%20%7Bx%7D%5E%7B4%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B64x%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%3E%20%20%5Cfrac%7B%20%7Bx%7D%5E%7B4%7D%20%7D%7B%20%7B%2864x%29%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%3E%20%20%5Cfrac%7B%20%7Bx%7D%5E%7B4%7D%20%7D%7B%20%28%7B64%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%29%5Ctimes%20%20%28%7Bx%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%29%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%3E%20%20%5Cfrac%7B%20%7Bx%7D%5E%7B4%7D%20%7D%7B%20%28%7B%28%20%7B4%7D%5E%7B3%7D%20%29%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%29%20%5Ctimes%28%20%20%7Bx%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%29%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%3E%20%20%20%5Cfrac%7B%20%7Bx%7D%5E%7B4%7D%20%7D%7B%20%28%7B4%7D%5E%7B%20%5Ccancel%7B3%7D%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B%20%5Ccancel%7B3%7D%7D%20%7D%20%29%20%5Ctimes%28%20%20%7Bx%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%29%7D%20%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%3E%20%20%5Cfrac%7B%20%7Bx%7D%5E%7B4%7D%20%7D%7B4%20%7Bx%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%3E%20%20%5Cfrac%7B%20%7Bx%7D%5E%7B4%20-%20%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%7D%7B4%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%3E%20%20%5Cfrac%7B%20%7Bx%7D%5E%7B%20%5Cfrac%7B12%20-%201%7D%7B3%7D%20%7D%20%7D%7B4%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%3E%20%20%5Cfrac%7B%20%7Bx%7D%5E%7B%20%5Cfrac%7B11%7D%7B3%7D%20%7D%20%7D%7B4%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%3E%20%20%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B%20%7Bx%7D%5E%7B11%7D%20%7D%20%7D%7B4%7D%20)
Answer:
2y = 3x - 8
y = 3/2x - 4
Work
-2x + 5(3/2x - 4) = -9
-2x + 15/2x - 20 (+20) = -9 (+20)
-4/2x + 15/2x = 11
11/2x * (2/11) = 11 (2/11)
x = 2
3(2) - 2y = 8
6 (-6) - 2y = 8 (-6)
-2y = 2
y = - 1
final answer:
x = 2
y = -1
Answer: 27/14
Step-by-step explanation:
(x+2)/x +(x-6)/3x = (2x+9)/5x
(3x+6)/3x + (x-6)/3x = (2x+9)/5x First term: [(x+2)/x]*(3/3) = (3x+6)/3x
(4x)/3x = (2x+9)/5x Combine (3x+6)/3x + (x-6)/3x [=(4x)/3x]
(4/3)*5x = 2x + 9 [(4x)/3x = 4/3] and multiply both sides by 5x
(20/3)x - 9 = 2x [(4/3)*5x] = (20/3)x; Subtract 9 from both sides
20x - 27 = 6x Multiply both sides by 3
14x = 27 Simplify
x = 27/14 And solve
Answer:
0
Step-by-step explanation:
Hi! We are given the limit expression:
If we directly substitute x = 2 then we get 0/0 which is an indeterminate form. Therefore, we need to find other methods to evaluate the limit that does not become an indeterminate form.
As for rational function with square root in it, we conjugate the expression by multiplying both denominator and numerator with the square root expression.
When two same square root expressions multiply each other, the square root is taken out as shown above.
From denominator, we can factor x²-4 to (x-2)(x+2) via differences of two squares.
Hence:
Cancel x-2.
Then substitute x = 2 which we receive 0/4 = 0.
Henceforth, the limit value of expression is 0.
