Use the graph below to determine the equation of the circle in a center radius form and a general form

Help me pleaseee :((

Drupady [299]

Answer: x > 6

The graph would be an empty circle on 6 going higher infinitely.

Step-by-step explanation:

5 0

3 years ago

Simplify the expression: 5(–4 + 3g)

MaRussiya [10]

Answer:

-20 + 15g

Step-by-step explanation:

5 multiplied by -4 is -20

5 multiplied by 3g is 15 g.

because these two variables do not both have a g with them, this is the most they can be simplified. hope this helps!

4 0

3 years ago

Read 2 more answers

The population of bacteria in a petri dish doubles every 24 h. The population of the bacteria is initially 500 organisms. How lo

liberstina [14]

Answer:

16.34 hours

Step-by-step explanation:

According to the given information we can see that the case is of exponential growth

Hence, we will use the formula

$A=P(2)^\frac{t}{24}$

Here A =800 is the amount that is needed to reach

P is the initial amount that is 500

We have to find the time it will take to reach 800 that is we need to find t

On substituting the values in the formula we get

$800=500(2)^\frac{t}{24}$

On simplification we get

$\Rightarrow\frac{8}{5}=(2)^\frac{t}{24}$

Taking log on both sides we get

$\Rightarrow\log\frac{8}{5}=\log(2)^\frac{t}{24}$

using $\log\frac{m}{n}=\log m-\log n$

And $\log a^m=m\log a$

$\Rightarrow\log{8}-\log{5}=\frac{t}{24}\log2$

Now substituting values of log 8=0.903, log 5=0.698 and log 2=0.301 we get

$\Rightarrow 0.903-0.698=\frac{t}{24}0.301$

$\Rightarrow 0.205=\frac{t}{24}0.301$

$\Rightarrow \frac{0.205}{0.301}\cdot 24=t$

$\Rightarrow t=16.34$

8 0

3 years ago

Read 2 more answers

What is the area of 10 cm 3 cm 7 cm 18 cm

Nesterboy [21]

Answer: 10 times 3 equals 30 and 7 times 18 equals 126. 126 plus 30 is 156 is the answer

Step-by-step explanation:math

8 0

3 years ago

Will mark brainliest for the correct answer!

romanna [79]

Part (a)

Focus on triangle PSQ. We have

angle P = 52

side PQ = 6.8

side SQ = 5.4

Use of the law of sines to determine angle S

sin(S)/PQ = sin(P)/SQ

sin(S)/(6.8) = sin(52)/(5.4)

sin(S) = 6.8*sin(52)/(5.4)

sin(S) = 0.99230983787513

S = arcsin(0.99230983787513)

S = 82.889762826274

Which is approximate

------------

Use this to find angle Q. Again we're only focusing on triangle PSQ.

P+S+Q = 180

Q = 180-P-S

Q = 180-52-82.889762826274

Q = 45.110237173726

Which is also approximate.

A more specific name for this angle is angle PQS, which will be useful later in part (b).

------------

Now find the area of triangle PSQ

area of triangle = 0.5*(side1)*(side2)*sin(included angle)

area of triangle PSQ = 0.5*(PQ)*(SQ)*sin(angle Q)

area of triangle PSQ = 0.5*(6.8)*(5.4)*sin(45.110237173726)

area of triangle PSQ = 13.0074347717966

------------

Next we'll use the fact that RS:SP is 2:1.

This means RS is twice as long as SP. Consequently, this means the area of triangle RSQ is twice that of the area of triangle PSQ. It might help to rotate the diagram so that line PSR is horizontal and Q is above this horizontal line.

We found

area of triangle PSQ = 13.0074347717966

So,

area of triangle RSQ = 2*(area of triangle PSQ)

area of triangle RSQ = 2*13.0074347717966

area of triangle RSQ = 26.0148695435932

------------

We're onto the last step. Add up the smaller triangular areas we found

area of triangle PQR = (area of triangle PSQ)+(area of triangle RSQ)

area of triangle PQR = (13.0074347717966)+(26.0148695435932)

area of triangle PQR = 39.0223043153899

------------

<h3>Answer: 39.0223043153899</h3>

This value is approximate. Round however you need to.

===========================================

Part (b)

Focus on triangle PSQ. Let's find the length of PS.

We'll use the value of angle Q to determine this length.

We'll use the law of sines

sin(Q)/(PS) = sin(P)/(SQ)

sin(45.110237173726)/(PS) = sin(52)/(5.4)

5.4*sin(45.110237173726) = PS*sin(52)

PS = 5.4*sin(45.110237173726)/sin(52)

PS = 4.8549034284642

Because RS is twice as long as PS, we know that

RS = 2*PS = 2*4.8549034284642 = 9.7098068569284

So,

PR = RS+PS

PR = 9.7098068569284 + 4.8549034284642

PR = 14.5647102853927

-------------

Next we use the law of cosines to find RQ

Focus on triangle PQR

c^2 = a^2 + b^2 - 2ab*cos(C)

(RQ)^2 = (PR)^2 + (PQ)^2 - 2(PR)*(PQ)*cos(P)

(RQ)^2 = (14.5647102853927)^2 + (6.8)^2 - 2(14.5647102853927)*(6.8)*cos(52)

(RQ)^2 = 136.420523798282

RQ = sqrt(136.420523798282)

RQ = 11.6799196828694

--------------

We'll use the law of sines to find angle R of triangle PQR

sin(R)/PQ = sin(P)/RQ

sin(R)/6.8 = sin(52)/11.6799196828694

sin(R) = 6.8*sin(52)/11.6799196828694

sin(R) = 0.4587765387107

R = arcsin(0.4587765387107)

R = 27.3081879220073

--------------

This leads to

P+Q+R = 180

Q = 180-P-R

Q = 180-52-27.3081879220073

Q = 100.691812077992

This is the measure of angle PQR

subtract off angle PQS found back in part (a)

angle SQR = (anglePQR) - (anglePQS)

angle SQR = (100.691812077992) - (45.110237173726)

angle SQR = 55.581574904266

--------------

<h3>Answer: 55.581574904266</h3>

This value is approximate. Round however you need to.

8 0

3 years ago