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BARSIC [14]
3 years ago
5

Find the missing length.

Mathematics
1 answer:
Lorico [155]3 years ago
6 0
The answer is B. 2ft
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prohojiy [21]
That would be  400 / 28 =  14.29 gallons to nearest hundredth
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3 years ago
Write<br> 83<br> 50<br> as a decimal.
Katyanochek1 [597]

Answer:

0.83,0.50

Step-by-step explanation:

Since there are 2 digits in 83, the very last digit is the "100th" decimal place.

So we can just say that .83 is the same as 83/100.

So your final answer is: .83 can be written as the fraction

7 0
3 years ago
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The half-life of the isotope Osmium-183 is 12 hours. Choose the equation below that gives the remaining mass of Osmium-183 in gr
raketka [301]

The given equations are incomprehensible, I'm afraid...

You're given that osmium-183 has a half-life of 12 hours, so for some initial mass <em>M</em>₀, the mass after 12 hours is half that:

1/2 <em>M</em>₀ = <em>M</em>₀ exp(12<em>k</em>)

for some decay constant <em>k</em>. Solve for this <em>k</em> :

1/2 = exp(12<em>k</em>)

ln(1/2) = 12<em>k</em>

<em>k</em> = 1/12 ln(1/2) = - ln(2)/12

Now for some starting mass <em>M</em>₀, the mass <em>M</em> remaining after time <em>t</em> is given by

<em>M</em> = <em>M</em>₀ exp(<em>kt </em>)

So if <em>M</em>₀ = 590 g and <em>t</em> = 36 h, plugging these into the equation with the previously determined value of <em>k</em> gives

<em>M</em> = 590 exp(36<em>k</em>) = 73.75

so 73.75 ≈ 74 g of Os-183 are left.

Alternatively, notice that the given time period of 36 hours is simply 3 times the half-life of 12 hours, so 1/2³ = 1/8 of the starting amount of Os-183 is left:

590/8 = 73.75 ≈ 74

6 0
3 years ago
Add the two expressions. 4.6x−3 and −5.3x+9 Enter your answer, in simplified form, in the box. PLEASE ANSWER FAST THIS IS A BIG
Ivan
To add the two expressions, we can write it as:

4.6x-3 + (-5.3x+9)

We can distribute the plus sign (which means just drop the parenthesis in this case):

4.6x-3-5.3x+9

Now, we can simplify by combining like terms:

-0.7x+6
4 0
3 years ago
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What is 0.04 is 1/10 of what number ?
Simora [160]
0.04= \frac{4}{100}\to\frac{1}{25} \\\\ \frac{1}{10} \ of \ x= \frac{1}{25} \\\\ \frac{1}{10}*x=\frac{1}{25} \\\\ \frac{x}{10}=\frac{1}{25} \\\\ \boxed{x=\frac{10}{25}\to\frac{2}{5}}
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3 years ago
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