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weqwewe [10]
3 years ago
11

Can somebody please help me with these 2 problems?

Mathematics
1 answer:
andrew11 [14]3 years ago
3 0
Give me 10 minutes and i’ll message you with the answer and respond here
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A whole number is also an integer. <br><br> True <br> False
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That is true. *******
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the Following table shows alexandra's investment options over the course of three years. Her initial investment was $1,000 . wri
Y_Kistochka [10]

The pattern in the given series of amount in the account are in the form of

arithmetic and geometric progression.

  • The function for Option 1 is;  \underline{ f(n) = 1,100 + (n - 1) \cdot 100}
  • The function for Option 2 is; \underline{f(n) = 1,100 \times  1.1^{(n - 1)}}

Reasons:

The given table of values is presented as follows;

\begin{tabular}{c|c|c|c|}Number of years&1&2&3\\Option 1 (Amount in dollars)&1,100&1,200&1,300\\Option 2 (Amount in dollars)&1,100&1,210&1,331\end{array}\right]

In Option 1, the amount in dollars for each year has a common difference of d = 100

The first term, a = 1,100

Therefore;

The Option 1 can be represented as an arithmetic progression , A.P. in the

form, tₙ = a + (n - 1)·d as follows;

For the Option 1, we have;

  • The amount in dollars after <em>n</em> years, \underline{ f(n) = 1,100 + (n - 1) \cdot 100}

For Option 2, it is possible to find;

1,331 ÷ 1,210 = 1,210 ÷ 1,100 = 1.1

Therefore;

The terms in the Option 2 have a common ratio of r = 1.1

The Option 2 is a geometric progression, G.P.

The first term in Option 2 is a = 1,100

Which gives, the nth term, tₙ = a·r⁽ⁿ ⁻ ¹⁾

Therefor;

  • The function for the Option 2 is; \underline{f(n) = 1,100 \times  1.1^{(n - 1)}}

Learn more about arithmetic and geometric progression here:

brainly.com/question/8932895

brainly.com/question/22977503

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2 years ago
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Answer:

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Step-by-step explanation:

9/1.25= 7.2

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WAN, LAN, PAN

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If x = –3 is the only x-intercept of the graph of a quadratic equation, which statement best describes the discriminant of the e
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\text{ if } \Delta=0\text{ then there is one x-intercept : }x=-\dfrac{b}{2a}\\\\&#10;\text{ if } \Delta\ \textless \ 0\text{ then there are no x-intercept : } x=\varnothing\\\\&#10;\text{ if } \Delta>0\text{ then there are two x-intercept : }x_1,x_2=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\\

<u>Answer </u>: <span>The discriminant is 0</span>
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